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Summarize the similarities are differences between the three simple bound cases considered in this chapter.

Short Answer

Expert verified

Similarly: All of the cases had a non-zero ground state Kinetic Energy and the form standing waves.

Differences: In case of infinite square well, the wave function doesn’t extend in to area outside walls, but in other cases it did.

Step by step solution

01

Step-1:Difference in the Energies

The three simple bond cases considered were the infinite well, the harmonics oscillators and the finite square well. All of those have a non-zero ground-state Kinetic Energy from standing waves. The harmonics oscillators and the infinite well can take on infinite number of states while the finite square well has a finite limit to the number of states it can hold.

02

Step-2:Difference in the Wave Functions

In the case of the infinite square well, the wave functions doesn’t extend into the area outside of the walls, but In the other two cases the wave function can extend into the classically forbidden area.

For the finite square well, the energy level becomes more spaced as more are added while the harmonic oscillators are evenly spaced.

Hence, the point of differences & similarities b/w three simple bound cases considered in this chapter are discussed above.

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Most popular questions from this chapter

If a particle in a stationary state is bound, the expectation value of its momentum must be 0.

(a). In words, why?

(b) Prove it.

Starting from the general expression(5-31) with p^in the place of Q, integrate by parts, then argue that the result is identically 0. Be careful that your argument is somehow based on the particle being bound: a free particle certainly may have a non zero momentum. (Note: Without loss of generality,ψ(x) may be chosen to be real.)

A particle is described by the wave function

ψ(x)=2/Πx2-x+1.25

(a) Show that the normalization constant2/Πis correct.

(b) A measurement of the position of the particle is to be made. At what location is it most probable that the particle would be found?

(c) What is the probability per unit length of finding the particle at this location?

What is the product of uncertainties determined in Exercise 60 and 61? Explain.

Show thatΔp=0p^ψ(x)=p¯ψ(x) that is, verify that unless the wave function is an Eigen function of the momentum operator, there will be a nonzero uncertainty in the momentumstarts with showing that the quantity

allspaceψ(x)(p^p¯)2ψ(x)dx

Is (Δp)2. Then using the differential operator form ofp^and integration by parts, show that it is also,

allspace{(p^p¯)ψ(x)}{(p^p¯)ψ(x)}dx

Together these show that ifΔpis. 0. then the preceding quantity must be 0. However, the Integral of the complex square of a function(the quantity in the brackets) can only be 0 if the function is identically 0, so the assertion is proved.

does the wave function have a well-defined ψ(x)=A(eikx+e-ikx)momentum? Explain.

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