Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Brass is a metal consisting principally of copper alloyed with a smaller amount of zinc, whose atoms do not alternate in a regular pattern in the crystal lattice but are somewhat randomly scattered about. The resistivity of brass is higher than that of either copper or zinc at room temperature, and it drops much slower as the temperature is lowered. What do these behaviors tell us about electrical conductivity in general?

Short Answer

Expert verified

Conductivity grows slowly as the temperature falls, unlike copper or zinc.

Step by step solution

01

Concept:

The valence electron becomes a free electron and thus the metal can conduct electricity. Thus, the electrical conductivity of copper increases with increasing temperature because the electrical conductivity of a metal is caused by the movement of electrons.

02

Step 2: Electrical conductivity:

Collisions between electrons and positive ions do not generate resistance in metals. Instead, the variation from regularity disrupts the electron wave, determining the metal's resistance. Brass, which is made up of atoms that do not alternate in a regular manner, has a far higher resistance than copper or zinc. This is due to the regular crystal pattern of copper or zinc.

The resistance of a metal increases as temperature rises and reduces as the temperature falls due to the vibration of the positive ions in the metal. The resistivity of brass is caused by flaws in the metal and is nearly temperature independent. As a result, as the temperature is dropped, the resistance of brass gradually diminishes. As a result, compared to copper or zinc, its conductivity rises slowly as the temperature decreases.

Hence, conductivity grows slowly as the temperature falls, unlike copper or zinc.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The effective force constant of the molecular โ€œspringโ€ in HCL is 480โ€ŠN/m, and the bond length is 0.13โ€Šnm.

(a) Determine the energies of the two lowest-energy vibrational states.

(b) For these energies, determine the amplitude of vibration if the atoms could be treated as oscillating classical particles.

(c) For these energies, by what percentages does the atomic separation fluctuate?

(d) Calculate the classical vibrational frequencyฯ‰vh=k/ฮผand rotational frequency for the rotational frequencyฯ‰rot=L/I, assume that L is the its lowest non zero value, 1(1+1)hand that the moment of inertia Iis ฮผa2.

(e) Is is valid to treat the atomic separation as fixed for rotational motion while changing for vibrational?

Question: The magnetic field at the surface of a long wire radius R and carrying a current I is ฮผ0I2ฯ€R . How large acurrent could a 0.1 mm diameter niobium wire carry without exceeding its 0.2 T critical field?

In diamond, carbonโ€™s four full (bonding) s and p spatial states become a band and the four empty(anti bonding) ones becomes a higher energy band. Considering the trend in the band gaps of diamond, silicon, and germanium, explain why it might not be surprising that โ€œcovalentโ€ tin behaves as a conducting metallic solid.

Starting with equation (10-4), show that if ฮ”n is-1 as a photon is emitted by a diatomic molecule in a transition among rotation-vibration states, but ฮ”โ„“can beยฑ1 . Then the allowed photon energies obey equation (10-6).

By the โ€œvectorโ€ technique of example 10.1 , show that the angles between all lobes of the hybridsp3states are 109.5ยฐ..

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free