Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Upon what definitions do we base the claim that the Ψ2px and Ψ2py states of equations 101 are related to x and y just as Ψ2pz is to z.

Short Answer

Expert verified

It is proven by converting Cartesian to spherical polar coordinates.

Step by step solution

01

A concept of polar coordinate

A polar coordinate is one of two numbers that identify a point in a plane based on its distance from a fixed point on a line and the angle that line makes with the fixed line.

02

Understanding the Similarities and Differences between these Wave Functions

States Ψ2px and Ψ2py are of the same shapes as Ψ2pz and they are all equivalent. The only difference between these states is the orientation of coordinates. These wave functions are defined based on spherical polar coordinates. γ,θ,ϕ.

03

Transformation of Coordinates

The transformation between Cartesian and spherical polar coordinates is

x=rsinθcosθy=rsinθcosθz=rcosθ

The wave functions of the 2px, 2py and 2pz states are given as

Ψx=Ψ2pxasinθcosθΨy=Ψ2pyasinθcosθΨz=Ψ2pzacosθ

Hence, from this its prove that the states 2px, 2py and 2pz depends on angles θand ϕ which are the same as that described in Cartesian coordinates for X, Y, and Z .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: - Verify using equation (10-12) that the effective mass of a free particle is m.

The isotope effect says that the critical temperature for the superconductivity decreases as the mass of the positive ions increases. Can you argue why it should decrease?

Exercise 29 outlines how energy may be extracted by transferring an electron from an atom that easily loses an electron from an atom that easily loses an electron to one with a large appetite for electrons , then allowing the two to approach , forming an ionic bond.

  1. Consider separately the cases of hydrogen bonding with fluorine and sodium bonding with fluorine in each case , how close must the ions approach to reach “break even” where the energy needed to transfer the electron between the separated atoms is balanced by the electrostatic potential energy of attraction? The ionization energy of hydrogen is 13.6 eV , that of sodium is 5.1 eV , and the electron affinity of fluorine is 3.40 Ev.
  2. Of HF and NaF , one is considered to be an ionic bond and the other a covalent bond . Which is which and Why?

By the “vector” technique of example 10.1 , show that the angles between all lobes of the hybridsp3states are 109.5°..

Question: Volumes have been written on transistor biasing, but Figure 10.45 gets at the main idea. Suppose that and that the "input" produces its own voltage . The total resistance is in the input loop, which goes clockwise from the emitter through the various components to the base, then back to the emitter through the base-emitter diode. this diode is forward biased with the base at all times 0.7 V higher than the emitter. Suppose also that Vcc = 12 V and that the "out- put" is350KΩ . Now. given that for every 201 electrons entering the emitter, I passes out the base and 200 out the collector, calculate the maximum and minimum in the sinusoidally varying

(a) Current in the base emitter circuit.

(b) Power delivered by the input.

(c) Power delivered to the output.

(d) Power delivered byVce.

(e) what does most of the work.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free