Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

When would a density of states be needed: in a sum over states? in a sum over energies? in an integral over energies? in an integral over states?

Short Answer

Expert verified
A Density of States (DOS) is not needed in sums over states and integral over states, but usually necessary in an integral over energies. It could be potentially useful during performing a sum over energies if energies are discretized.

Step by step solution

01

Sums over states

A Density of States (DOS) isn't strictly needed in a sum over states since the sum is going over individual states; not trying to gauge very many states there are in any give energy interval. However, it can be used as a shortcut if the states and energies happen to be quantised and disposed such as to form a tidy DOS.
02

Sums over energies

A DOS could be used in a sum over energies, although sums over energy are relatively less common than integrals because energies are continuous in most of solid state physics. We would switch to a sum over energies only if the energies are discretized due to some reason.
03

Integrals over energies

A DOS is almost always needed in an integral over energies. Because the DOS gives the number of states in a given energy interval, these calculations need a DOS to make sure that how many states are being covered in the energy range they're integrating over.
04

Integrals over states

In integrals over states, Density of States (DOS) is not necessary. Each state in this case is counted individually during integration.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sum Over States
In quantum mechanics and solid-state physics, a sum over states is a method used to calculate physical quantities by adding up contributions from all the possible quantum states of a system. However, there is a distinction between a simple summation and the need for the Density of States (DOS). When we sum over states, we are considering each individual quantum state separately. In such calculations, the DOS, which highlights how many states are available per interval of energy, isn't essential. However, when these states are quantized in a regular pattern, DOS can serve as a shortcut by enabling us to evaluate sums quickly for large numbers of states.

For example, if we were to calculate the total magnetic moment of a material, we would sum the contributions from each state. If these states are discrete and well-defined, we might not require DOS. Nevertheless, DOS becomes beneficial when considering systems with a vast number of states where direct summation can be cumbersome or when the energy levels form a continuum.
Integral Over Energies
When transitioning from discrete to continuous systems, the Density of States (DOS) becomes a critical concept. In this context, an integral over energies is often required instead of a simple sum. The DOS informs us of the number of accessible states within a specific energy interval, which is crucial for calculating integrals over those energies. This is a common scenario in solid-state physics, where energy levels form bands instead of discrete lines.

For instance, to find the heat capacity of a solid, we would integrate the energy states' contributions over the relevant energy range. The DOS makes such calculations feasible by allowing us to incorporate the distribution of states with energy into our models. Without DOS, we would struggle to account for the varied number of states available at different energy levels as we integrate over a particular energy range.
Quantum Mechanics
The foundation of modern physics lies within quantum mechanics, a theory that describes the physical properties of nature at the scale of atoms and subatomic particles. Quantum mechanics introduces the concept of quantized energies, wave-particle duality, and probabilistic nature of physical phenomena. The DOS is a quantum mechanical concept as well, relating to how many different ways particles can be arranged within quantized energy levels. Understanding the DOS is crucial for exploring and predicting various quantum phenomena such as electronic configuration, spectral lines, and the behavior of semiconductors or insulators at different temperatures.

In quantum mechanics, every particle or system has multiple possible states, each with a specific energy. The DOS is essentially a map detailing the density of these quantum states across the energy spectrum, providing insights into how particles like electrons will occupy these states.
Solid State Physics
Diving into the realm of condensed matter, solid state physics focuses on the properties of solids, particularly the electron behavior that determines the electrical, thermal, and optical characteristics of materials. One of the central constructs in this field is the electronic band structure, which the DOS helps to elucidate. The DOS reflects how closely packed the energy levels are within bands and gaps and influences properties such as electrical conductivity and heat capacity.

For example, in conductors, the DOS at the Fermi energy determines how many electrons are available to contribute to electrical conductivity. In semiconductors and insulators, the DOS in the band gap becomes significant for understanding electronic transitions and optoelectronic properties. By analyzing the DOS, physicists and engineers can tailor materials for specific applications by manipulating their electronic structures through doping or by creating novel nanostructures.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

We claim that the famous exponential decrease of probability with energy is natural, the vastly most probable and disordered state given the constraints on total energy and number of particles. It should be a state of maximum entropy! The proof involves mathematical techniques beyond the scope of the text, but finding support is good exercise and not difficult. Consider a system of 11 oscillators sharing a total energy of just 5hω0. In the symbols of Section 9.3,N=11 and M=5. (a) Using equation (99), calculate the probabilities of n being 0.1,2. and 3. (b) How many particles. Nn, would be expected in each level? Round each other nearest integer. (Happily. the number is still 11 . and the energy still she0 ) What you have is a distribution of the energy that is as close to expectations is possible, given that numbers at each level in a real case are integers. (c) Entropy is related to the number of microscopic ways the macrostate can be obtained. and the number of ways of permuting particle labels with N0. N1,N2, an dN1 fixed and totaling 11 is 11!/(N0!N1! N2!N3). (See Appendix J for the proof.) Calculate the number of ways for your distribution. (d) Calculate the number of ways if there were 6 particles in n=0.5 in n=1, and none higher. Note that this also has the same total energy. (e) Find at least one other distribution in which the 11 oscillators share the same energy, and calculate the number of ways. (f) What do your findings suggest?

Determine the relative probability of a gas molecule being within a small range of speeds around 2rms  to being in the same range of speeds around vrms .

We based the exact probabilities of equation (9.9) on the claim that the number of ways of adding N distinct nonnegative integers/quuntum numbers to give a total of M is \(\{M+N-1) ! /\left[M^{\prime}(N-1) !\right]\). Verify this claim (a) for the case N=2,M=5 and (b) for the case N=5,M=2

A "cold" object, T1=300 K, is briefly put in contact with a "hot" object, T2400 K, and 60 J of heat flows from the hot object to the cold one. The objects are then separated, their temperatures having changed negligibly due to their large sizes. (a) What are the changes in entropy of each object and the system as a whole? (b) Knowing only that these objects are in contact and at the given temperatures, what is the ratio of the probabilities of their being found in the second (final) state W that of their being found in the first (initial) state? What does chis result suggest?

Equation (927) gives the density of states for a system of oscillators but ignores spin. The result, simply one state per energy change of ω0 between levels. is incorrect if particles are allowed diff erent spin states at each level. but modification to include spin is easy. From Chapter 8 , we know that a particle of spin s is allowed 2s+1 spin orientations, so the number of states at each level is simply multiplied by this factor. Thus, D(E)=(2s+1)/ω0 (a) Using this density of states, the definition  Nheud (2s+1)=δ, and N=0N(E)D(E)dE calculate the parameter B in the Boltzmann distribution (931) and show that the distribution can thus be tewritten as N(E)Bolu =εkBT1eE/LBT (b) Algue that if kBTδ, the occupation number is much less than I for all E.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free