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What is special about a metastable state, and why is it so useful in a laser? Why wouldn't a nonmetastable state at the same energy work?

Short Answer

Expert verified
The metastable state is crucial in a laser system due to its unusually long lifespan, allowing for the principle of stimulated emission which leads to laser action. Without this metastable state, atoms at the same energy would rapidly decay, thereby not allowing sufficient time for stimulated emission to occur and thus failing to amplify the light signal.

Step by step solution

01

Understand the Metastable State

In a laser system, the metastable state is a stage where atoms are excited to an energy level that is unusually long-lived. The atoms can stay in this state for a significant period before they decay to a lower energy state. This long-lived excited state is what we call metastable state.
02

Explain the Benefit of Metastable State in a Laser

The metastable state is particularly useful in laser systems due to the principle of 'stimulated emission'. When an atom in the metastable state comes in contact with a photon that precisely matches the energy difference between the metastable and lower state, it can be stimulated to decay and produce an additional photon identical to the incoming one. This process is the cornerstone of the laser system, creating a chain reaction that amplifies light and makes the production of a coherent and powerful beam of light possible.
03

Compare with a Non-metastable State at Same Energy

A non-metastable state at the same energy wouldn't work for creating a laser because the atoms would not stay in an excited state for long enough to allow for stimulated emission. As soon as an atom reached the excited state, it would rapidly decay back to a lower energy state, releasing its energy as a photon. However, it would not wait for an incoming photon to trigger stimulated emission. Without a sufficient number of atoms in the excited state, stimulated emission and thus laser action would not occur.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laser Physics
Laser physics revolves around understanding how we can make atoms or molecules emit light in a structured and amplified way. Lasers stand for Light Amplification by Stimulated Emission of Radiation. A laser is a device that emits light through a process of optical amplification, relying heavily on the principles of stimulated emission.
This happens when an external source, such as a flash of light or an electric current, gives atoms energy, exciting them to a higher energy state. In laser physics, attaining a proper energy balance and maintaining atoms in a state that allows for the slow release of energy is crucial.
  • Lasers are used in various applications like medical treatments, communication, and entertainment.
  • They depend on the behavior of atoms at different energy levels to produce consistent and intense beams of light.
  • Mastering laser physics involves understanding how energy is added to and released from atoms.
Understanding these basic principles helps us harness the power of light in innovative ways.
Stimulated Emission
Stimulated emission is a critical concept in creating lasers. This process occurs when an excited atom or molecule, which is in a higher energy state, shifts to a lower energy state, resulting in the emission of a photon. The amazing part is this photon has the same wavelength, phase, and direction as the incoming one.
This is essentially amplifying the light and is central to building a laser beam. For stimulated emission to take place, the energy of the incoming photon needs to match the energy difference between the excited state and a lower state very precisely.
  • During stimulated emission, it's possible to produce more photons, helping in "amplifying" the light.
  • This process is necessary to create the kind of coherent, concentrated light beams that lasers are known for.
  • The environment must be appropriately controlled to achieve and sustain stimulated emission.
Understanding stimulated emission enables us to understand how lasers can create powerful beams that are used globally in different technologies.
Energy Levels in Atoms
Atoms are composed of a nucleus and electrons, which orbit the nucleus at different energy levels. These energy levels are quantized, meaning that electrons exist in quantum states and can only occupy specific energy levels rather than a spectrum. When a photon hits an atom, it can be absorbed, causing an electron to move to a higher energy level, termed as excitation.
If the energy provided by the photon matches the energy difference between the current and a higher state, the electron transitions to that level.
  • Energy levels determine how and when electrons can move between different states, releasing photons.
  • A metastable state is an energy level that allows electrons to stay excited longer, vital for laser operation.
  • The alignment and structure of these levels are crucial in the technology, design, and operation of lasers.
By understanding energy levels and their dynamics, we can better utilize them for technologies like lasers, communications, and other applications needing precise photon control.

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Most popular questions from this chapter

Given an arbitrary thermodynanic systemn, which is larger. the number of possible macrostates, or the number of possible microstates, or is it impossible to say? Explain your answer. (For most systems, both are infinite, but it is still possible to answer the question)

The Fermi energy in a quantum gas depends inversely on the volume. Basing your answer on simple Chapter S-type quantum mechanics (not such quaint notions as squeezing classical particles of finite volume into a container too small), explain why.

A two-sided room contains six particles, \(a, b, c, d\). \(e .\) and \(f\), with two on the left and four on the right. (a) Describe the macrostate. (b) Identify the possible microstates. (Note: With only six particles, this isn't a thermodynamic system, but the general idea stitl applies. and the number of combinations is tractable.)

Example 9.2 obtains a ratio of the number of particles expected in the \(n=2\) state to that in the ground state. Rather than the \(n=2\) state, consider arbitrary \(n\). (a) Show that the ratio is \(\frac{\text { number of energy } E_{n}}{\text { number of energy } E_{1}}=n^{2} e^{-13.6 \mathrm{cV}\left(1-n^{-2}\right) / k_{\mathrm{B}} T}\) Note that hydrogen atom energies are \(E_{n}=\) \(-13.6 \mathrm{eV} / \mathrm{r}^{2}\) (b) What is the limit of this ratio as \(n\) becomes very large? Can it exceed \(1 ?\) If so, under what condition(s)? (c) In Example 9.2, we found that even at the temperature of the Sun's surface \((\sim 6000 \mathrm{~K})\), the ratio for \(n=2\) is only \(10^{-8}\). For what value of \(n\) would the ratio be \(0.01 ?\) (d) Is it realistic that the number of atoms with high \(n\) could be greater than the number with low \(n\) ?

This problem investigates what fraction of the available chayge must he tranferred from one conductor to another to produre a typical contact potential. (a) As a rough appnximation, treat the conductors as \(10 \mathrm{~cm} \times\) \(10 \mathrm{c} \mathrm{m}\) square plates \(2 \mathrm{~cm}\) apart - a parallel-plate capactor \(-\) so that \(q=C V\), where \(C=\varepsilon_{\mathrm{p}}\left(0.01 \mathrm{~m}^{2} / 0.02 \mathrm{~m}\right)\). How much charge must be iransferred from one plate to the other to produce a potential difference of \(2 \mathrm{~V}\) ? (b) Approximately what fruction would this be of the total number of conduction electrons in a \(100 \mathrm{~g}\) piece of copper, which has one conduction electron per atem?

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