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All other things being equal, should the spin-orbit interaction be a larger or smaller effect in hydrogen as \(n\) increases? Justify your answer.

Short Answer

Expert verified
The Spin-Orbit interaction effect in hydrogen would be smaller as \(n\) increases. This is because the electron is further from the nucleus and thus experiences a weaker magnetic field, resulting in a weaker interaction between the electron spin and its orbital motion.

Step by step solution

01

Understand Principal Quantum Number \(n\)

The principal quantum number, \(n\), determines the energy level or the shell of an electron in an atom. As \(n\) increases, the electron is found in a higher energy level further away from the nucleus.
02

Relate Spin-Orbit Interaction and Quantum Number

The spin-orbit interaction is affected by the magnitude of the electron's orbital angular momentum, which is dependent on the quantum number \(n\). In a hydrogen atom, as \(n\) increases, the orbital radius also increases, meaning the electron is further away from the nucleus.
03

Conclusion on Spin-Orbit interaction variation

The effect of the Spin-Orbit interaction would decrease as \(n\) increases. This is because the electron is further away from the nucleus and thus experiences a weaker magnetic field from the nucleus. As a result, the interactions between the electron spin and its orbital motion would be weakened as \(n\) increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
The principal quantum number, denoted as \(n\), is a fundamental concept in quantum mechanics that specifies the energy level and size of the electron orbit in an atom. Think of \(n\) as the 'address' of an electron, indicating on which floor of an atomic 'skyscraper' the electron resides. As \(n\) increases, the electron's energy increases and it lives further away from the nucleus. This is akin to an elevator moving up in a building—the higher the floor, the farther away from the lobby you are.

For hydrogen, which has a single electron, this quantum number becomes especially significant because it's directly linked to the size of the electron's orbit and its energy. The concept is critical for understanding how electrons interact with the magnetic fields within the atom, which further influences the overall behavior of the atom, including chemical bonding and spectral emissions.
Orbital Angular Momentum
Orbital angular momentum is a bit like the 'twirl' of an electron around the nucleus. Imagine a planet orbiting the sun—the way it moves in its path defines its orbital angular momentum. In quantum physics, this momentum is quantized, which means it can only take on specific, discrete values.

The orbital angular momentum depends on the principal quantum number \(n\) and the azimuthal (or orbital) quantum number \(\ell\), where \(\ell\) can range from 0 to \(n-1\). It determines the shape of the electron's orbit and influences the magnetic properties of the atom. The larger the angular momentum, the more 'spread out' the electron's orbit becomes. This is crucial because an electron with greater angular momentum will have a weaker interaction with the magnetic field of the nucleus due to its increased distance from the nucleus.
Magnetic Field in Atom
In the tiny world of an atom, the magnetic field is like the silent force orchestrating an elegant dance of electrons. It arises mainly from the movement of electrons and the intrinsic magnetic moment of particles. In hydrogen, the sole electron generates a magnetic field due to its charge and its motion around the nucleus—a movement that itself is affected by the electron's orbital angular momentum.

Since the electron's motion creates a current, it gives rise to its own magnetic field, which interacts with its spin—a fundamental property related to its intrinsic angular momentum. This interaction is what we refer to as the spin-orbit interaction. In simpler terms, as the electron whirls around the nucleus, it feels its own version of a 'magnetic breeze' which affects how it spins. As you move further away from the nucleus (at higher principal quantum numbers), this 'breeze' weakens, illustrating why the spin-orbit interaction decreases with increasing \(n\). Understanding this interplay is key to mastering the complexities of atomic physics.

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Most popular questions from this chapter

Identify the different total angular momentum states (j. \(m_{i}\) ) allowed a 3 d electron in a hydrogen atom.

As the \(2 p\) levels fill. from \(Z=5\) to \(10,\) the elements' first ionization energies tend to increase. But, as Figure 8.16 clearly mdicates, it is slightly easier to remove an electron from \(Z=8\) oxygen than from \(Z=7\) nitrogen. What might explain this?

What is the angle between the spins in a triplet state?

A good electron thief needs a trap at low energy to entice its prey. A poor electron shepherd will have at least some of its tlock dangling out at high energy. Consider rows 2 and 5 in the periodic table. Why should fluorine, in row \(2,\) be more reactive than iodine. in row 5 , while lithium, in row 2 , is less reactive than \mathrm{\\{} u b i d i u m , ~ i n ~ r o w ~ 5 ?

The 21 cm Line: One of the most important windows to the mysteries of the cosmos is the 21 cm line. With it, astronomers map hydrogen throughout the universe. An important trait is that it involves a highly forbidden transition that is, accordingly, quite long-lived. But it is also an excellent example of the coupling of angular momenta. Hydrogen's ground state has no spin-orbit interaction - for \(\boldsymbol{\theta}=0,\) there is no orbit. However, the proton and electron magnetic moments do interact. Consider the following simple model. (a) The proton sees itself surrounded by a spherically symmetric cloud of Is electron, which has an intrinsic magnetic dipole moment/spin that, of course, has a direction. For the purpose of investigating its effect on the proton, treat this dispersed magnetic moment as behaving effectively like a single loop of current whose radius is \(a_{0}\), then find the magnetic tield at the middle of the loop in tenns of \(e, h, m_{e}, \mu_{0},\) and \(a_{0} .\) (b) The proton sits right in the middle of the electron's magnetic moment. Like the electron. the proton is a spin- \(\frac{1}{2}\) particle, with only two possible orientations in a magnetic field. Noting, however, that its spin and magnetic moment are parallel rather than opposite, would the interaction energy be lower with the proton's spin aligned or antialigned with that of the electron'? (c) For the proton, \(g_{p}\) is \(5.6 .\) Obtain a rough value for the energy difference between the two orientations. (d) What would be the wavelength of a photon that carries away this energy difference?

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