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Write the electronis configurations for phosphorus. germanium. and cesium.

Short Answer

Expert verified
The electron configurations for Phosphorus (P), Germanium (Ge), and Cesium (Cs) are: \[P: 1s^2 2s^2 2p^6 3s^2 3p^3, \] \[Ge: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^2, \] and \[Cs: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^1. \]

Step by step solution

01

Electron Configuration of Phosphorus

Find phosphorus in the periodic table. Its atomic number is 15, meaning it has 15 electrons. The electron configuration can be written as: \[ 1s^2 2s^2 2p^6 3s^2 3p^3\]
02

Electron Configuration of Germanium

Germanium's atomic number is 32. So, it has 32 electrons. The electron configuration of germanium would be: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^2.\]
03

Electron Configuration of Cesium

Cesium has an atomic number of 55. Its electron configuration would be: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^1. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The atomic number is a fundamental property of chemical elements. It represents the number of protons found in the nucleus of an atom of the element.
Each element in the periodic table has a unique atomic number, which determines the element's identity. For example, phosphorus has an atomic number of 15, meaning it has 15 protons in its nucleus. Likewise, germanium has an atomic number of 32, and cesium has an atomic number of 55. These numbers not only define the element but also give us the number of electrons in a neutral atom.
  • The atomic number helps in predicting the electron configuration of an element, as electrons fill the lowest energy levels first.
  • The element's chemical behavior and periodic table placement are directly related to its atomic number.
  • Understanding atomic numbers is crucial for learning more complex concepts like isotopes, where atoms have the same number of protons but different numbers of neutrons.
Periodic Table
The periodic table is a powerful tool for chemists and students alike. It arranges all known elements in an informative grid according to their atomic numbers and recurring chemical properties.
It allows you to quickly determine a lot about an element, including its electron configuration, based on its position.
  • The table is organized into rows called periods and columns known as groups or families.
  • Elements in the same group often share similar properties because they have the same number of electrons in their outer shell.
  • The periodic law states that many properties of elements are periodic functions of their atomic numbers.
For example, phosphorus, germanium, and cesium have their electron configurations defined by where they are located. Studying their placement in the periodic table helps in understanding the patterns of their electron arrangements.
Electron Shells
Electron shells are layers of electrons that orbit the nucleus of an atom. They fill up in a specific order, starting from the closest shell to the nucleus. This filling order determines the electron configuration for each element.
With each shell able to hold a certain number of electrons, knowing how they fill can help explain many chemical behaviors and characteristics.
  • Electron shells are labeled as K, L, M, N, and so on, corresponding to 1, 2, 3, 4, etc.
  • The number and arrangement of electrons in these shells determine how an element will react chemically.
  • The main electron shells further consist of subshells, typically labeled as s, p, d, and f.
For phosphorus, germanium, and cesium, understanding their electron configurations involves knowing how their electrons are distributed across these shells. As electrons occupy the lowest energy levels first, we observe specific patterns naturally occurring as some shells fill up fully before others begin filling.

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Most popular questions from this chapter

Compare and contrast the angular momentum and magnetic moment related to or bital mot ion with those that ane intrinsic.

Whether a neutral whole atom behaves as a boson or a fermion is independent of \(Z\), instead depending entirely on the number of neutrons in its nucleus. Why? Whatrs it about this number that determines whether the atom is a boson or a fernion?

A good electron thief needs a trap at low energy to entice its prey. A poor electron shepherd will have at least some of its tlock dangling out at high energy. Consider rows 2 and 5 in the periodic table. Why should fluorine, in row \(2,\) be more reactive than iodine. in row 5 , while lithium, in row 2 , is less reactive than \mathrm{\\{} u b i d i u m , ~ i n ~ r o w ~ 5 ?

As is done for helium in Table 8.3 , determine for a carton atom the various states allowed according to \(\angle S\) coupling. The coupling is between carbon's two \(2 p\) electrons (its filled 2 s subshell not participating). one of which always remains in the \(2 p\) state. Consider cases in which the other is as high as the \(3 d\) level. (Note: When both electrons are in the \(2 p\), the exclusion principle Iestricts the number of states. The only allowed states are those in which \(s_{r}\) and \(\ell_{T}\) are both even or both odd.)

Exercise 44 gives an antisymmetric multiparticle state for two particles in a box with opposite spins. Another antisymmetric state with spins opposite and the same quantum numbers is $$ \psi_{n}\left(x_{1}\right) \downarrow \psi_{n}\left(x_{2}\right) \uparrow-\psi_{n}\left(x_{1}\right) \uparrow \psi_{n}\left(x_{2}\right) \downarrow $$ Refer to these states as \(\mid\) and 11 . We have tended to characterize exchange symmetry as to whether the state's sign changes when we swap particle labels. but we could achieve the same result by instead swapping the particles' stares, specifically the \(n\) and \(n^{\prime}\) in equation \((8-22)\). In this exercise. we look at swapping only parts of the state-spatial or spin. (a) What is the exchange symmeiry - symmetric (unchanged). antisymmetric (switching sign), or neither-of multiparticle states 1 and \(\mathrm{II}\) with respect to swapping spatial states alone? (b) Answer the same question. but with respect to swapping spin states/arrows alone. (c) Show that the algebraic sum of states 1 and \(\mathrm{II}\) may be written \(\left(\psi_{n}\left(x_{1}\right) \psi_{n}\left(x_{2}\right)-\psi_{n}\left(x_{1}\right) \psi_{n}\left(x_{2}\right)\right)(\downarrow T+\uparrow \downarrow)\) where the left arrow in any couple represents the spin of particle 1 and the right arrow that of particle 2 (d) Answer the same questions as in parts \((a)\) and (b). but for this algebraic sum. (e) Is the sum of states I and 11 still antis ymmetric if we swap the particles? total-spatial plus spin -states? (f) If the two particles repel each other, would any of the three multiparticle states - l. II, and the sum - be preferred? Explain.

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