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Show that the frequency at which an electron's intrinsic magnetic dipole moment would process in a magnetic field is given by \(\omega \cong e B / m_{c}\). Calculate this frequency for a field of \(10 \mathrm{~T}\)

Short Answer

Expert verified
The frequency at which an electron's intrinsic magnetic dipole moment would process in a 10T magnetic field is approximately \( 1.76 \times 10^{12} rad/sec \).

Step by step solution

01

Understanding the Procession Frequency

The precession frequency \( \omega \) of an electron in a magnetic field is given by the formula \( \omega = \gamma B \), where \( \gamma \) is the gyromagnetic ratio, and \( B \) is the magnetic field. The gyromagnetic ratio for an electron is given by \( \gamma = \frac{e}{m_{c}} \), where \( e \) is the elementary charge and \( m_{c} \) is the mass of the electron. Substituting this into the previous formula gives us \( \omega = \frac{e}{m_{c}} B \).
02

Simplifying the Expression

The expression can be simplified as \( \omega \cong \frac{e B}{m_{c}}\). This is the frequency at which an electron's intrinsic magnetic dipole moment would process in a magnetic field.
03

Calculating the Precession Frequency

Given that \( B = 10 T \) (Tesla), the frequency can be calculated by substituting \( B \) into the equation: \( \omega = \frac{e \cdot 10}{m_{c}} \). The elementary charge, \( e \), is approximately \( 1.602 \times 10^{-19} C \) (Coulombs), and the electron mass, \( m_{c} \), is approximately \( 9.109 \times 10^{-31} Kg \). Substituting these values gives: \( \omega = \frac{1.602 \times 10^{-19} \cdot 10}{9.109 \times 10^{-31}} = 1.76 \times 10^{12} rad/sec \). This is the precession frequency of the electron's magnetic dipole moment in the given field.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gyromagnetic Ratio
The gyromagnetic ratio is a fundamental property that relates the magnetic moment and angular momentum of a particle. For electrons, this is a key element when discussing their behavior in a magnetic field.

In physics, the gyromagnetic ratio, often denoted as \( \gamma \), is the ratio of the magnetic dipole moment to the angular momentum. Specifically for an electron, the expression is given by \( \gamma = \frac{e}{m_c} \), where:
  • \( e \) is the elementary charge \( (1.602 \times 10^{-19} \text{ C}) \)
  • \( m_c \) is the mass of the electron \( (9.109 \times 10^{-31} \text{ kg}) \)
This ratio is crucial in determining how electrons behave under the influence of a magnetic field as it directly links the magnetic dipole moment and the precession frequency, giving rise to phenomena like Electron Paramagnetic Resonance (EPR).

Understanding \( \gamma \) helps provide insight into the fundamental interactions between magnetic fields and quantum mechanical electrons.
Magnetic Dipole Moment
The magnetic dipole moment is an essential concept in understanding electron behavior in magnetic fields. A dipole moment occurs whenever there's a separation of positive and negative charges within a system.

For electrons, the intrinsic magnetic dipole moment arises from their spin and charge, contributing to their overall magnetic properties. This moment is analogous to tiny magnets within electrons and is represented mathematically as a vector.
  • It contributes to an electron's response in magnetic fields.
  • This moment affects how electrons align themselves in magnetic fields, leading to precession, a rotational movement around the magnetic field lines.
The precession frequency can be calculated by relating the magnetic dipole moment with the applied magnetic field, showcasing the direct connection in quantum physics.

This core concept illustrates how electrons interact at a microscopic level, which can drastically impact material properties on a larger scale.
Electron in Magnetic Field
An electron placed in a magnetic field exhibits fascinating behavior due to its intrinsic properties such as charge and magnetic dipole moment.

When subjected to a magnetic field, an electron's magnetic dipole attempts to align with the field. However, due to its quantum nature, this alignment results in precession. This is similar to how a spinning top wobbles around its vertical axis.
  • The precession of electrons is a critical concept in fields such as nuclear magnetic resonance (NMR) and magnetic resonance imaging (MRI).
  • Its frequency is determined by factors such as the strength of the magnetic field and the gyromagnetic ratio of the electron.
In the exercise, it was shown that an electron in a \( 10 \) Tesla magnetic field has a precession frequency of approximately \(1.76 \times 10^{12} \text{ rad/sec}\).

Understanding this behavior helps bridge the gap between quantum mechanics and practical application in technology and materials science.

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Most popular questions from this chapter

The \(K_{a}\) line in copper is a very common one to use in \(X\) -ray ciystallography. To produce it, electrons are accelerated through a potential difference and smashed into a copper target. Section 7.8 gives the energies in a hydrogenlike atom as \(Z^{2}\left(-13.6 \mathrm{eV} / \mathrm{n}^{2}\right)\). Making the reasonable approximation that an \(n=1\) electron in copper orbils the nucleus and half of its fellow \(n=1\) electron. being unaff ected by the roughly spherical cloud of other electrons around it, estimate the minimum accelerating potential needed to make a hole in copper's \(K\) shell.

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Figure 8.3 shows the Stern-Gerlach apparans. It reveals that spin- \(\frac{1}{2}\) particles have just two possible spin states. Assume that when these rwo beams are separated inside the channel (though still near its centerline). we can choose to block one or the other for study. Now a second such apparatus is added after the first. Their channels are aligned. but the second one is rotated about the \(x\) -axis by an angle \(\phi\) from the first. Suppose we block the spin-down beam in the first apparatus, allowing only the spin-up beam into the second. There is no wave function for spin. but we can still talk of a probability amplitude, which we square to give a probability. After the first apparatus' spin-up beam passes chrough the second apparatus, the probability amplitude is \(\cos (\phi / 2) T_{2 n d}+\sin (\phi / 2) b_{2 n d}\). where the arrows indicate the two possible findings for spin in the second apparatus. (a) What is the probability of finding the particle spin up in the second apparatus? Of finding it spin down? Argue thatthese probabilities make sense individually for representative values of \(\phi\) and that their sum is also sensible. (b) By contrasting this spin prohability anplitude with a sporial probability amplitude, such as \(\psi(x)=A e^{-b x^{2}}\), argue that although the surhitrariness of \(\phi\) gives the spin case an infinite number of values. it is still justified to refer to it as 8 "two-state system." while the spatial case is an infinite.state system.

The wave functions for the ground and first excited states of a simple hartnonic oscillator are \(A e^{-b x^{2} / 2}\) and B.xe \(^{-b x^{2} / 2}\). Suppose you have two particles occupying these two states. (a) If distinguishable, an acceptable wave function would be \(A e^{-b x_{1}^{2} / 2} B x_{2} e^{-b x_{2}^{2} / 2}\). Calculate the probability that both particles would be on the positive side of the origin and divide by the total probability for both being found over all values of \(x_{1}\) and. \(x\), (This kind of nonnalizing-as-we-go will streamline things.) (b) Suppose now that the particles are indistin. guishable. Using the \(\pm\) symbol to reduce your work. calculate the same probability ratio, but assuming that their multiparticle wave function is either symmetric on antisymmetric. Comment on your results.

Does circulating charge require both an gular momentum and magnetic moment? Consider positive and neg. ative charges simultaneously circulating and countercirculating.

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