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A dipole withour angular momenturn can simply rotate to align with the field (though i would oscillate uniess it could shed energy). One with angular momentum cannot. Why?

Short Answer

Expert verified
A dipole with no angular momentum can simply align itself with the field because it reaches a state of minimum energy this way. One with angular momentum will continue to rotate, despite the presence of the field, due to the conservation of angular momentum. The continued rotation means that the dipole will precess around the field direction rather than aligning with it.

Step by step solution

01

Understanding Dipoles and Magnetic Fields

A dipole in a magnetic field will always try to align itself with the field. This is because when the dipole aligns with the field, the system reaches a state of minimum potential energy. This principle applies to both an electric dipole in an electric field and a magnetic dipole in a magnetic field.
02

The Role of Angular Momentum

Angular momentum is a measure of the amount of rotation an object has. It is a conserved quantity, meaning it will not change unless an external torque acts on it. In the context of a dipole in a magnetic field, it means that if a dipole had angular momentum before entering the field, it will keep spinning even after it enters the field.
03

Energy Dissipation

Now imagine a dipole with no angular momentum. It could simply align with the magnetic field, reaching a state of minimum energy. If any oscillations occur during this process,friction-like effects could dissipate energy, and the dipole would eventually come to rest, perfectly aligned with the field.
04

Dipoles with Angular Momentum

However, if the dipole had nonzero angular momentum, things are different. Because of the conservation of angular momentum, the dipole cannot simply stop rotating and align with the field. This continuous rotation means that the angle between the dipole and the magnetic field periodically changes, causing the dipole to precess around the direction of the magnetic field.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Momentum
Angular momentum is a fundamental concept that describes the rotation of an object. Think of it like an object's tendency to keep spinning. For a dipole, having angular momentum means it's already in motion, spinning around a certain axis. This is a key factor because angular momentum is a conserved quantity, meaning it doesn't just disappear.
  • If an object has angular momentum, it will continue spinning at the same rate and direction unless acted upon by an outside force.
  • In a magnetic field, a dipole with angular momentum can't just stop and line up with the field instantly, it keeps on spinning.
This is important because even in a new environment—like entering a magnetic field—the dipole's inherent spin won't just vanish. The dipole's rotation affects how it interacts with the magnetic field and prevents it from simply aligning without any precession or change to its angular state.
Magnetic Field
A magnetic field is a region where magnetic forces can be experienced by objects with magnetic properties. It's like an invisible web pulling or orienting magnets and magnetic dipoles towards itself. In the context of this exercise, when a magnetic dipole enters a magnetic field, it seeks to align itself in a particular way—the direction that minimizes potential energy.
  • This alignment is because a system always "prefers" to be in a state of lower energy. Think of it like water flowing to the lowest point; energy systems do something similar.
  • A dipole without angular momentum will naturally turn and face the direction of the magnetic field lines.
However, once there's angular momentum at play, this natural alignment doesn't occur straightforwardly. The magnetic field tries to influence the dipole, but the conservation of angular momentum causes more complexity in this interaction, causing it to move in a more complex manner such as precession.
Energy Dissipation
Energy dissipation refers to the process by which a system loses energy over time, usually as heat or thru friction-like effects. For a dipole, once it starts aligning with the magnetic field, if it has no angular momentum, energy can naturally dissipate and allow a perfect alignment.
  • Without angular momentum, a dipole can slowly shed energy, becoming progressively more aligned until it rests in this state.
  • An oscillating dipole can lose energy via processes similar to friction, slowing down any wobbling or movement.
However, for a dipole with angular momentum, continuous rotation prevents it from reaching full alignment. Instead of stopping, it precesses—a behavior similar to how a spinning top wobbles. As a result, the energy dissipation isn't enough to stop its motion entirely unless external forces are applied to counteract the rotating momentum.

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Most popular questions from this chapter

The spin-orbit interaction splits the hydrogen 4 f state into many. (a) Identify these states and rank them in order of increasing energy. (b) If a weak external magnetic field were now introduced (weak enough that it does not disturb the spin-orbit coupling), into how many difierent energies would each of these states be split?

The electron is known to have a radius no larger than \(10^{-18} \mathrm{~m}\) If actually produced by circulating mass, its intrinsic angular momentum of roughly \(\hbar\) would imply very high speed. even if all that mass were as far from the axis as possible. (a) Using simply \(r p\) (from \(|r \times p|\) ) for the angular momentum of a mass at radius \(r\). obtain a rough value of \(p\) and show that it would imply highly relativistic speed. (b) At such speeds, \(E=y m c^{2}\) and \(p=\gamma\) mu combine to give \(E \cong p c\) (just as for the speedy photon). How does this energy compare with the known intenial energy of the electron?

What is the minimum possible energy for five (noninteracting) spin- \(\frac{1}{2}\) particles of mass \(m\) in a onedimensional box of length \(L ?\) What if the particles were spin-1? What if the particles were spin- \(\frac{3}{2} ?\)

The Zeeman effect occurs in sodium just as in hydrogen - sodium's lone 3 s valence electron behaves much as hydrogen's 1.5. Suppose sodium atoms are immersed in a \(0.1 \mathrm{~T}\) magnetic field. (a) Into how many levels is the \(3 p_{1 / 2}\) level split? (b) Determine the energy spacing between these states. (c) Into how many lines is the \(3 p_{1 / 2}\) to \(3 s_{1 / 2}\) spectral line split by the field? (d) Describe quantitatively the spacing of these lines. (e) The sodium doublet \((589.0 \mathrm{nm}\) and \(589.6 \mathrm{nm}\) ) is two spectral lines. \(3 p_{3 n} \rightarrow 3 s_{1 / 2}\) and \(3 p_{1 / 2} \rightarrow 3 s_{1 / 2}\) which are split according to the two different possible spin-orbit ener gies in the \(3 p\) state (see Exercise 60 ). Detemine the splitting of the sodium doublet (the energy diff erence between the two photons). How does it compare with the line splitting of part (d), and why?

The well-known sodium doublet is two yellow spectral lines of very close wavelength. \(589.0 \mathrm{nm}\) and \(589.6 \mathrm{nm} .\) lt is caused by splitting of the \(3 p\) energy level. due to the spin-orbit interaction. In its ground state, sodium's single valence electron is in the \(3 s\) level. It may be excited to the next higher level, the \(3 p\), then emit a photon as it drops back to the \(3 s\). However. the \(3 \rho\) is actually two levels. in which \(L\) and \(S\) are aligned and antialigned. IIn the notation of Section 8.7 these are. respectively. the \(3 p_{3 / 2}\) and the \(3 p_{1 n}\) ) Because the transitions stan from slightly different initial energies yet have identical final energies(the \(3 s\) having no orbital angular momentum to lead to spin- orbit interaction), there are two differenl wavelengths possible for the emitted photon. Calculate the difference in energy between the two photons. From this, obtain a rough value of the average strength of the internal magnetic field experienced by sodium's valence electron.

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