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Exercises 7888 refer to a particle of mass m described by the wave function $$ \psi(x)=\left\{2a3xeaxx>00x<0\right. $$ Calculate the uncertainty in the particle's momentum.

Short Answer

Expert verified
The uncertainty in the particle's momentum can be calculated by finding the difference between mean square momentum and the square of the mean momentum using the wavefunction. The mathematical process involves evaluating certain integrals and differentiating the wavefunction. The exact numerical result depends on the concrete normalization constant a and mass m of a particle.

Step by step solution

01

Mean value of square of momentum

The operator for the square of the momentum is p2=2d2dx2. So, the mean value is given by the following integral: p2=2ψ(x)d2dx2ψ(x)dx Also, consider that ψ(x)=ψ(x) because the wavefunction is real.
02

Square of the mean value of momentum

The operator for the momentum is p=iddx. So, the square of the mean value of the momentum is given by: p2=(iψ(x)ddxψ(x)dx)2
03

Use the uncertainty relation

The uncertainty of the momentum is given by the following equation according to Heisenberg's uncertainty principle: (Δp)2=p2p2 Substitute the result from step 1 and step 2 in this equation to get the desired result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uncertainty Principle
The Heisenberg Uncertainty Principle is a key underpinning of quantum mechanics, highlighting the intrinsic limitations in measuring complementary properties of a particle, such as position and momentum. It states that the more precisely one property is known, the less precisely the other can be known, encapsulated by the formula:
ΔxΔp2where Δx is the uncertainty in position and Δp is the uncertainty in momentum, and is the reduced Planck’s constant.
This principle emphasizes the probabilistic nature of quantum mechanics, reflecting the idea that particles do not have definite locations or speeds at the atomic scale until they are measured. Instead, these properties are described by probabilities.
Wave Function
A wave function, commonly denoted by ψ(x), is a mathematical description of the quantum state of a particle or system. It contains all the necessary information about a system's state and its interaction with the environment. In quantum mechanics, the wave function is a solution to the Schrödinger equation.
The square of its absolute value, |ψ(x)|2, gives the probability density of finding a particle at a specific position. For example, in the given function:
ψ(x)={2a3xeaxx>0 0x<0it shows us that the probability of finding the particle decreases exponentially as x increases for x>0, and it is zero for x<0.
This function shapes the way we predict a particle's behavior within a quantum system.
Momentum Operator
In quantum mechanics, the momentum operator is a crucial tool that represents the momentum of a particle in the position space representation. It is given by the expression:
p^=iddxwhere p^ is the momentum operator, is the reduced Planck's constant, and i is the imaginary unit.
This operator functions as part of the Schrödinger equation, acting on wave functions to yield momentum-related information.
  • In the given exercise, the momentum operator is applied to the wave function ψ(x) to determine the mean momentum.
  • The momentum operator allows us to calculate expected values when used with the wave functions, highlighting the deep connections between states and measurements in quantum systems.
By working with this operator, physicists can predict how particles behave, offering insights into their dynamic properties.

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Most popular questions from this chapter

A comet in an extremely elliptical orbit about a star has, of course, a maximum orbit radius. By comparison, its minimum orbit radius may be nearly 0. Make plots of the potential energy and a plausible total energy E versus radius on the same set of axes. Identify the classical turning points on your plot.

Quantization is an important characteristic of systems in which a particle is bound in a small region. Why "small," and why "bound's?

In Section 5.5. it was shown that the infinite well coergis follow simply from Λ=h/p, the fornulafor kinelic encrgy. p2/2m; and a famous standing-wave condition λ=2Un. The arguments are perfectly valid when the potential energy is 0 (inside the well) and L is strictly conskant, but they can also be useful in other cases. The length L allowed the wave should be roughly the distance between the classical tuming points, where there is no kinetic eneigy left. Apply these arguments to the oscillator potential energy, U(x)=12κx2. Find the location x of the classical tuming point in terms of E; use nwice this distance for L: then insert this into the infinite well eneigy fonnula so that E appears on both sides. Thus far, the procedure Ieally only deals with kinctic energy. Assume, as is tue for a classical oscillator, that there is as much potential eneigy, on average, as kinetic energy. What do you obtain for the quantized energies?

Equation (516) gives infinite well energies. Because equation (522) cannot be solved in closed form, there is no similar compact formula for finite well energies. Still, many conclusions can be drawn without one. Argue on largely qualitative grounds that if the walls of a finite well are moved closer together but not changed in height, then the well must progressively hold fewer bound states. (Make a clear connection between the width of the well and the height of the walls.)

Write out the total wave function Ψ(x,t) for an electron in the n=3 state of a 10nm wide infinite well. Other than the symbols x and t, the function should include only numerical values.

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