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Refer to a particle of mass m trapped in a half-infinite well, with potential energy given by $$ U(x)=\left\{x0\00<x<L\U0xL\right.$$ Write solutions to the Schrödinger equation appropriate in the various regions, impose required continuity conditions, and obtain the energy quantization condition:

Short Answer

Expert verified
The energy quantization condition for a particle of mass m in a half-infinite well is given by ktan(kL)=α, where k=2mE2 and α=2m(U0E)2 are used to solve the Schrödinger equation.

Step by step solution

01

Frame the Schrödinger Equation

The time-independent Schrödinger equation is given by 22md2ψdx2+U(x)ψ=Eψ where is the reduced Planck’s constant, m is the mass of the particle, ψ is the wave function, U(x) is the potential energy and E is the total energy of the system. The particle's behavior is determined by solving this equation with the potential U(x).
02

Apply the Schrödinger Equation to Region 1 ( x0)

Due to the infinite potential energy for this region, we require the wave function ψ to be finite everywhere. So, ψ1=0 for this region.
03

Apply the Schrödinger Equation to Region 2 ( 0<x<L)

For this region, potential energy U=0. This turns the Schrödinger equation into 22md2ψdx2=Eψ. This is a simple harmonic oscillator equation, with solutions of the form ψ2=Asin(kx)+Bcos(kx), where k2=2mE2. Since ψ1=0, we require ψ2 to be continuous at x=0, which implies B=0. Thus, the wave function for region 2 is ψ2=Asin(kx).
04

Apply the Schrödinger Equation to Region 3 ( xL)

For this region, potential energy U=U0, where U0>E. Thus, the Schrödinger equation becomes 22md2ψdx2+U0ψ=Eψ which simplifies to 22md2ψdx2=(U0E)ψ. From this type of equation, the wave function for region 3 should be of the form ψ3=Ceαx+Deαx, where α2=2m(U0E)2. Due to that the wave function must remain finite as x approaches infinity, C=0, and the function for this region becomes ψ3=Deαx.
05

Meet the Continuity Condition

We need to ensure ψ and dψdx are continuous at x=L. This gives us two equations: ψ2(L)=ψ3(L) and dψ2dx(L)=dψ3dx(L). From here, we can find the quantization condition: ktan(kL)=α. This is the energy quantization condition for this problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Well
The potential well is a fundamental concept in quantum mechanics, pivotal to understanding how particles behave when they are confined in a restricted region of space. In this exercise, we consider a half-infinite potential well, which means that the potential energy is infinite at one end and has a finite value at the other. This restriction effectively traps the particle in a limited region.

In the half-infinite well:
  • The potential is infinite for values of x0, thus a particle cannot exist there, i.e., the wave function ψ1=0.
  • Between 0<x<L, the potential is zero, allowing the particle to exist freely.
  • For xL, the potential becomes a finite value U0, still restricted but not infinite, influencing the particle's wave function ψ3 beyond this point.
The energy states of the particle hinge upon these potential conditions, creating zones where the particle can and cannot exist.
Energy Quantization
Energy quantization emerges from the conditions imposed on the particle's wave functions within the potential well. Unlike classical systems where energy can vary continuously, quantum mechanics requires that only certain discrete energy levels are permissible for particles in confined spaces.

In this problem, due to boundary and continuity requirements at points x=0 and x=L, the energy levels are quantized. This means that the particle can only possess specific energies, derived from the quantization condition ktan(kL)=α, where:
  • k is related to the particle's energy E in the region 0<x<L.
  • α stems from the potential U0 encountered in xL.
The requirement for this continuity and boundary alignment translates to the wave function uncertainties manifesting as discrete energy levels. Thus, the particle's energy is split into distinct packets, important for understanding the particle's stability and state transitions.
Wave Functions
Wave functions are a cornerstone of quantum mechanics, offering a complete description of a quantum state of a particle. Mathematically represented as ψ(x), these functions forecast the probability of finding a particle in a specific location.

For each region of the potential well:
  • In the region x0, since the potential is infinite, the wave function ψ1=0 as the particle cannot exist there.
  • In the region 0<x<L, the wave function ψ2=Asin(kx) is derived from solving the simplified Schrödinger equation where the potential is zero.
  • In the region xL, the wave function fits the form ψ3=Deαx, indicating an exponential decay as the particle virtually tunnels into the potential barrier.
The conditions at the boundaries ensure that these wave functions remain continuous and differentiable across the different regions of the well. This results, through the principles of superposition and interference, in the emergent quantized energy levels we observe in quantum wells.

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Most popular questions from this chapter

Write out the total wave function Ψ(x,t) for an electron in the n=3 state of a 10nm wide infinite well. Other than the symbols x and t, the function should include only numerical values.

Harmonic Oscillator: The hannonic oscillator can be solved exactly for the quantized energies, and here we compare those results with a numerical approach. Along with the values of m and discussed above, we choose our units so that the spring constant x is also 1 . The potential energy function U(x) is then simply 12x2 For Δx, use 0.001. (a) Following the above guidelines on choosing 1β(0) and ψ(Δx), test both odd and even functions at different trial values of E by finding ψ at all positive multiples of Δx out 10x=4 and plotting the results. Note that because of the functions' symmetries there is no need to plot negative values of x. Find four allowed energies. (b) What tells you that an energy is correct? (c) Compare your results with the exact values given in equation (526).

A classical particle confined to the positive x - cxis experiences a force whose potential energy is U(x)=1x22x+1( S1 units ) (a) By finding its minimum value and determining its behaviors at x=0 and x= toe, sketch this potential energy. (b) Suppose the particle has an energy of 0.5 . Find any turning points. Would the particle be bound? (c) Suppose the particle has an energy of 2.0 J. Find any turning points. Would the particle be bound?

Just what is stationary in a stationary state? The particle? Something else?

Exercise 53 outlines a procedure for predicting how the quantum-mechanically allowed energies for a harmotic oscillator should depend on a quantum number. In essence, allowed kinetic energies are the particle-in-abox energtes, except the length L is replaced by the distance between classical tuming points, expressed in terms of E. Apply this procedure to a potenu'al energy of the fonn U(x)=b/x, where b is a constant. Assume that at the origin there is an infinitely high wall, making it one turning point, and determine the other tuming pomt in terms of E. For the average potential energy. use its value at half way between the tuming points. again in terms of E. Find an expression for the allowed energies in terms of m,b, and n. (Although threedimensional. the hydrogen atom potential energy is of this form. and the allowed energy levels depend on a quantum number exactly as this simple model predicts.)

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