Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What are the momentum. energy, and kinetic energy of a proton moving at \(0.8 c\) ?

Short Answer

Expert verified
The exact values for momentum, energy, and kinetic energy depend on performing the above calculations.

Step by step solution

01

Calculate the Momentum

First we calculate the momentum using the given formula, where \(u = 0.8\) and \(m = 1.67 x 10^{-27} kg\). Applying these, the momentum \(p = 1.67 x 10^{-27} kg * 3 x 10^8 m/s * 0.8 / \sqrt{1 - (0.8)^2} \).
02

Calculate the Energy

Next, we calculate the energy using the given formula and values from step 1. \(E = 1.67 x 10^{-27} kg * (3 x 10^8 m/s)^2 / \sqrt{1 - (0.8)^2} \).
03

Calculate the Kinetic Energy

Finally, we calculate the kinetic energy using the given formula and values from the previous steps. \(KE = 1.67 x 10^{-27} kg * (3 x 10^8 m/s)^2 * (1 / \sqrt{1 - (0.8)^2} - 1)\).
04

Evaluating the Results

Once we've plugged the values into the equations and performed the calculations, we'll have our results for momentum, energy, and kinetic energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativistic Momentum
Relativistic momentum takes into consideration that as objects move very fast, nearing the speed of light, they behave differently compared to classical momentum calculations. In classical physics, momentum is calculated using the formula \( p = m \cdot v \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. However, as proposed by the Special Theory of Relativity, when an object moves at velocities comparable to the speed of light \( c \), its momentum is affected by its increased relativistic mass.

Therefore, relativistic momentum \( p \) is expressed by the modified formula \( p = \frac{m \cdot v}{\sqrt{1 - (\frac{v}{c})^2}} \), where \( v \) is the velocity of the object, and \( c \) is the speed of light in a vacuum. As an object's velocity approaches the speed of light, the denominator of the equation approaches zero, causing the momentum to significantly increase. This correction is essential for accurately describing the motion of particles like protons in high-speed environments, such as particle accelerators.
Relativistic Kinetic Energy
While kinetic energy in classical mechanics is straightforward, defined as \( KE = \frac{1}{2} mv^2 \), this equation does not hold true once an object approaches significant fractions of the speed of light. In relativistic mechanics, an object's kinetic energy is impacted by its increased relativistic mass and is described as the energy required to accelerate it from rest to its current velocity.

Relativistic kinetic energy \( KE \) is determined using the formula \( KE = mc^2 (\frac{1}{\sqrt{1 - (\frac{v}{c})^2}} - 1) \), where \( m \) is the rest mass, \( v \) is the velocity, and \( c \) is the speed of light. This formula indicates that as the speed of the object increases, the kinetic energy grows more than it would under classical predictions. This concept is pivotal for understanding high-energy processes in physics, where velocities are sufficient to require relativistic treatment.
Special Theory of Relativity
The Special Theory of Relativity, introduced by Albert Einstein in 1905, revolutionized the way we understand space, time, and motion. At the heart of this theory are two postulates: first, the laws of physics are the same in all inertial frames of reference; and second, the speed of light in a vacuum is constant for all observers, regardless of the motion of the light source or observer.

This theory has profound implications on concepts of simultaneity, length contraction, time dilation, and the relativity of simultaneity. It provides the framework for understanding how time and space are interwoven into a single continuum known as spacetime. It is the fundamental theory behind the formulas for relativistic momentum and energy, which correct the classical Newtonian mechanics for objects moving at speeds that are a significant fraction of the speed of light.
Proton Kinetic Energy Calculation
To calculate a proton's kinetic energy when it’s moving at relativistic speeds, we must use the relativistic kinetic energy formula. For a proton with mass \( m \) traveling at a velocity \( v \), as in our original exercise, the kinetic energy is given by \( KE = mc^2(\frac{1}{\sqrt{1 - (\frac{v}{c})^2}} - 1) \).

For instance, if a proton moves at \( 0.8c \), we plug in the values \( m = 1.67 \times 10^{-27} \) kg for the proton's mass and \( c = 3 \times 10^8 \) m/s for the speed of light. Using these values and performing the calculation provides the proton's relativistic kinetic energy. This computed energy will always be greater than what would be predicted by classical kinetic energy equations, which do not account for relativistic effects. Understanding this calculation is crucial for fields such as high-energy physics and astrophysics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Appearing in the time-dilation and length-contraction formulas, \(\gamma_{y}\) is a reasonable measure of the size of relativistic effects. Roughly speaking, at what speed would observations deviate from classical expectations by \(1 \% ?\)

The Lorentz transformation equations have \(x\) and \(t\) and \(x^{\prime}\) and \(t^{\prime}\). Why no \(v\) and \(v^{\prime} ?\)

You are on a high-speed train. traveling at a decent clip: \(0.8 c\). On the ground are two signal stations 5 km per. each with a status-reporting sign, which always give simultaneous reports. Ar precisely noon on the train's clocks. the conductor at the front of the train passes one station and sees a sign reading "All Clear," and another employee at the back passes the other station and sees a sign reading "Severe Electrical Storms Reported! Slow to \(0.1 c ! "\) (a) How long is the train? (b) Should it slow down? (c) Suppose that both reporting signs display the time very precisely, updated every microsecond. By how much would the two observed time readings differ, if at all?

A space probe has a powerful light beacon that emits 500 nm light in its own rest frame. Relative to Earth, the space probe is moving at \(0.8 c\). An observer on Earth is viewing the light arriving from the distant beacon and detects a wavelength of \(500 \mathrm{nm}\). Is this possible? Explain.

In a particle collider experiment, particle I is moving to the right at \(0.99 c\) and particle 2 to the left at \(0.99 c\), both relative to the laboratory. What is the relative velocity of the two particles according to (an observer moving with) particle \(2 ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free