Chapter 2: Problem 70
What are the momentum. energy, and kinetic energy of a proton moving at \(0.8 c\) ?
Short Answer
Expert verified
The exact values for momentum, energy, and kinetic energy depend on performing the above calculations.
Step by step solution
01
Calculate the Momentum
First we calculate the momentum using the given formula, where \(u = 0.8\) and \(m = 1.67 x 10^{-27} kg\). Applying these, the momentum \(p = 1.67 x 10^{-27} kg * 3 x 10^8 m/s * 0.8 / \sqrt{1 - (0.8)^2} \).
02
Calculate the Energy
Next, we calculate the energy using the given formula and values from step 1. \(E = 1.67 x 10^{-27} kg * (3 x 10^8 m/s)^2 / \sqrt{1 - (0.8)^2} \).
03
Calculate the Kinetic Energy
Finally, we calculate the kinetic energy using the given formula and values from the previous steps. \(KE = 1.67 x 10^{-27} kg * (3 x 10^8 m/s)^2 * (1 / \sqrt{1 - (0.8)^2} - 1)\).
04
Evaluating the Results
Once we've plugged the values into the equations and performed the calculations, we'll have our results for momentum, energy, and kinetic energy.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Relativistic Momentum
Relativistic momentum takes into consideration that as objects move very fast, nearing the speed of light, they behave differently compared to classical momentum calculations. In classical physics, momentum is calculated using the formula \( p = m \cdot v \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. However, as proposed by the Special Theory of Relativity, when an object moves at velocities comparable to the speed of light \( c \), its momentum is affected by its increased relativistic mass.
Therefore, relativistic momentum \( p \) is expressed by the modified formula \( p = \frac{m \cdot v}{\sqrt{1 - (\frac{v}{c})^2}} \), where \( v \) is the velocity of the object, and \( c \) is the speed of light in a vacuum. As an object's velocity approaches the speed of light, the denominator of the equation approaches zero, causing the momentum to significantly increase. This correction is essential for accurately describing the motion of particles like protons in high-speed environments, such as particle accelerators.
Therefore, relativistic momentum \( p \) is expressed by the modified formula \( p = \frac{m \cdot v}{\sqrt{1 - (\frac{v}{c})^2}} \), where \( v \) is the velocity of the object, and \( c \) is the speed of light in a vacuum. As an object's velocity approaches the speed of light, the denominator of the equation approaches zero, causing the momentum to significantly increase. This correction is essential for accurately describing the motion of particles like protons in high-speed environments, such as particle accelerators.
Relativistic Kinetic Energy
While kinetic energy in classical mechanics is straightforward, defined as \( KE = \frac{1}{2} mv^2 \), this equation does not hold true once an object approaches significant fractions of the speed of light. In relativistic mechanics, an object's kinetic energy is impacted by its increased relativistic mass and is described as the energy required to accelerate it from rest to its current velocity.
Relativistic kinetic energy \( KE \) is determined using the formula \( KE = mc^2 (\frac{1}{\sqrt{1 - (\frac{v}{c})^2}} - 1) \), where \( m \) is the rest mass, \( v \) is the velocity, and \( c \) is the speed of light. This formula indicates that as the speed of the object increases, the kinetic energy grows more than it would under classical predictions. This concept is pivotal for understanding high-energy processes in physics, where velocities are sufficient to require relativistic treatment.
Relativistic kinetic energy \( KE \) is determined using the formula \( KE = mc^2 (\frac{1}{\sqrt{1 - (\frac{v}{c})^2}} - 1) \), where \( m \) is the rest mass, \( v \) is the velocity, and \( c \) is the speed of light. This formula indicates that as the speed of the object increases, the kinetic energy grows more than it would under classical predictions. This concept is pivotal for understanding high-energy processes in physics, where velocities are sufficient to require relativistic treatment.
Special Theory of Relativity
The Special Theory of Relativity, introduced by Albert Einstein in 1905, revolutionized the way we understand space, time, and motion. At the heart of this theory are two postulates: first, the laws of physics are the same in all inertial frames of reference; and second, the speed of light in a vacuum is constant for all observers, regardless of the motion of the light source or observer.
This theory has profound implications on concepts of simultaneity, length contraction, time dilation, and the relativity of simultaneity. It provides the framework for understanding how time and space are interwoven into a single continuum known as spacetime. It is the fundamental theory behind the formulas for relativistic momentum and energy, which correct the classical Newtonian mechanics for objects moving at speeds that are a significant fraction of the speed of light.
This theory has profound implications on concepts of simultaneity, length contraction, time dilation, and the relativity of simultaneity. It provides the framework for understanding how time and space are interwoven into a single continuum known as spacetime. It is the fundamental theory behind the formulas for relativistic momentum and energy, which correct the classical Newtonian mechanics for objects moving at speeds that are a significant fraction of the speed of light.
Proton Kinetic Energy Calculation
To calculate a proton's kinetic energy when itβs moving at relativistic speeds, we must use the relativistic kinetic energy formula. For a proton with mass \( m \) traveling at a velocity \( v \), as in our original exercise, the kinetic energy is given by \( KE = mc^2(\frac{1}{\sqrt{1 - (\frac{v}{c})^2}} - 1) \).
For instance, if a proton moves at \( 0.8c \), we plug in the values \( m = 1.67 \times 10^{-27} \) kg for the proton's mass and \( c = 3 \times 10^8 \) m/s for the speed of light. Using these values and performing the calculation provides the proton's relativistic kinetic energy. This computed energy will always be greater than what would be predicted by classical kinetic energy equations, which do not account for relativistic effects. Understanding this calculation is crucial for fields such as high-energy physics and astrophysics.
For instance, if a proton moves at \( 0.8c \), we plug in the values \( m = 1.67 \times 10^{-27} \) kg for the proton's mass and \( c = 3 \times 10^8 \) m/s for the speed of light. Using these values and performing the calculation provides the proton's relativistic kinetic energy. This computed energy will always be greater than what would be predicted by classical kinetic energy equations, which do not account for relativistic effects. Understanding this calculation is crucial for fields such as high-energy physics and astrophysics.