Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

\(\mathrm{A}(t=0\), a bright beacon at the origin flashes, sending light uniformly in all directions. Anna is moving at speed \(v\) in the \(+x\) direction relative to the beacon and passes through the origin at \(l=0\). (a) Show that according to Anna, the only light with a positive \(x^{\prime}\) -component is that which in the beacon's reference frame is within an angle \(\theta=\cos ^{-1}(v / c)\) of the \(+x\) -axis. (b) What are the limits of \(\theta\) as \(v\) approaches 0 and as it approaches \(c\) ? (c) The phenomenon is called the headlight effect. Why?

Short Answer

Expert verified
a) The angle, θ, is derived as \(\cos^{-1}\left(\frac{v}{c}\right)\). b) As \(v\) approaches 0, \(\theta\) approaches \(\frac{π}{2}\) and as \(v\) approaches \(c\), \(θ\) approaches 0. c) The phenomenon is called the headlight effect because light is increasingly focused into a narrower area in front of an object as the object's speed approaches the speed of light.

Step by step solution

01

Calculate the Angle

This is a relativistic problem and we are given that Anna is moving at a speed v relative to the beacon. According to Anna, the only light with a positive \(x^{\prime}\)-component corresponds to the light that is moving in a direction that makes an angle θ with the +x direction. Here, the light path is making an angle with the direction of motion of Anna in the beacon's frame. We can use the relation between the direction of motion and the speed to derive the expression for θ. This can be done using the equation for the speed of light \(c\), the speed of Anna \(v\), and the angle θ between the direction of motion and the light path. Using the definition of cosine, we find: \(\cos(\theta) = \frac{v}{c}\), which gives the desired relationship: \(\theta = \cos^{-1}\left(\frac{v}{c}\right)\).
02

Determine the Limits of θ

To find the limits of \(\theta\) as \(v\) approaches 0 and \(c\), respectively, we apply the definition of θ with these limits. If \(v\) approaches 0, then \(\frac{v}{c}\) approaches 0, and \(\cos^{-1}(0)\) is \(\frac{\pi}{2}\), so \(\theta\) approaches \(\frac{\pi}{2}\). If \(v\) approaches \(c\), then the fraction \(\frac{v}{c}\) approaches 1, and \(\cos^{-1}(1)\) is 0, therefore \(θ\) approaches 0.
03

Explain the Phenomenon

The phenomenon is called the headlight effect because of the way light behaves according to Special Relativity. As Anna moves faster and faster towards the speed of light, the light from the beacon is increasingly focused into a smaller and smaller cone in front of Anna, similar to a headlight. Anna will thus perceive the light to be coming from a very narrow area in front of her when moving at high speeds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Headlight Effect
In the realm of Special Relativity, the headlight effect is a fascinating phenomenon that describes how light appears to focus in the direction of motion for an observer traveling at high speeds. Imagine Anna moving swiftly past a beacon, which emits light uniformly in all directions. To Anna, due to her relativistic motion, the light doesn't spread evenly anymore. Instead, it seems to be concentrated in a cone-shaped region in front of her. This is what we call the headlight effect.
The effect becomes noticeable as the speed of the observer approaches a significant fraction of the speed of light. As Anna's speed increases, the light is squeezed into a tighter and tighter cone, much like how the beams of a flashlight or car headlights focus forward. This means:
  • The light appears brighter and more intense in the forward direction.
  • Less light reaches the observer from other directions.
This effect has practical significance in areas like astrophysics, helping us understand the appearance of objects moving close to the speed of light.
Relativistic Motion
Relativistic motion is essential for understanding how different observers perceive events. In Anna’s scenario, relativistic effects become evident due to her high velocity close to the speed of light. Regular rules of motion don't suffice when speeds approach such extremes.
  • The laws of physics remain the same for Anna, but time and space measurements don't.
  • Anna's viewpoint is different than that of the beacon's, as her time (time dilation) and space (length contraction) are altered.
In the light beacon's frame, light spreads out in a symmetric fashion. However, for Anna, who is moving relative to the beacon, this symmetry breaks. This is because the speed of light remains constant (\(c\)) in all frames according to the principle of relativity. Thus, any light not traveling extremely close to her forward path seems to vanish from her field of view.
Cosine Inverse
To understand what Anna sees, we need to calculate the angle \(\theta\) between her direction of motion and the path of the incoming light. The mathematical tool used here is the inverse cosine function, denoted as \(\cos^{-1}\).
  • The relationship \(\theta = \cos^{-1}\left(\frac{v}{c}\right)\) helps determine which light rays reach Anna.
  • The equation tells us how light increasingly narrows into a beam as Anna's speed \(v\) approaches \(c\) (the speed of light).
For small speeds (\(v \approx 0\)), \(\cos^{-1}\left(0\right)\) gives \(\theta = \frac{\pi}{2}\) radians (or 90 degrees), meaning Anna sees light from a wide angle. However, as \(v\) nears \(c\), \(\frac{v}{c}\) approaches 1, leading to \(\cos^{-1}(1) = 0\). This shows that Anna perceives light from an increasingly narrow region ahead.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If it is fundamental to nature that a given mass has a critical radius at which something extraordinary happens (i.e., a black hole forms), we might guess that this radius should depend only on the mass and fundamental constants of nature. Assuming that \(r_{\text {critical }}\) depends only' on \(M, G\), and \(c\), show that dimensional analysis gives the equation for the Schwarzschild radius to within a multiplicative constant.

Derive the following expressions for the components of acceleration of an object, \(a_{x}^{\prime}\) and \(a_{y}^{\prime}\), in frame \(S^{\prime}\) in terms of its components of acceleration and velocity in frame S. $$ \begin{array}{c} a_{x}^{\prime}=\frac{a_{x}}{\gamma_{v}^{3}\left(1-\frac{u_{x} v}{c^{2}}\right)^{3}} \\ a_{y}^{\prime}=\frac{a_{y}}{\gamma_{v}^{2}\left(1-\frac{u_{x} v}{c^{2}}\right)^{2}}+\frac{a_{x} \frac{u_{y} v}{c^{2}}}{\gamma_{v}^{2}\left(1-\frac{u_{x} v}{c^{2}}\right)^{3}} \end{array} $$

The Doppler effect formula involves two speeds, \(v\) and c. The Doppler formula for sound involves three speeds (source, listener, and sound). Why a different number?

If an object actually occupies less space physically when moving, it cannot depend on the direction we define as positive. As we know, an object aligned with the direction of relative motion is contracted whether it is fixed in frame \(S\) and viewed from \(S^{\prime}\), or the other way around. Use this idea to argue that distances along the \(y\) - and \(y^{\prime}\) -axes cannot differ at all. Consider a post of length \(L_{0}\) fixed in frame \(S\), jutting up from the origin along the \(+y\) -axis, with a saw at the top poised to slice off anything extending any higher in the passing frame \(S\). Also consider an identical post fixed in frame \(S\). What happens when the origins cross?

Consider the collisions of two identical particles. each of mass \(m_{0}\). In experiment \(A\), a particle moving at \(0.9 c\) strikes a stationary particle. (a) What is the total kinetic energy before the collision? (b) In experiment \(B\), both particles are moving at a speed \(u\) (relative to the lab), directly roward one another. If the total kinetic energy bef ore the collision in experiment \(B\) is the same as that in experiment A, what is \(u\) ? c) In both experiments, the particles stick together. Find the mass of the resulting single particle in each experiment. In which is more of the initial kinetic energy converted to mass?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free