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A plank. fixed ro a sled at rest in frame \(S\), is of length \({L}_{0}\) and makes an angle of \(L_{0}\) with the \(x\) -axis. Later. the sled zooms through frame \(S\) at constant speed \(v\) parallel to the r-axis. Show that according to an observer who remains at rest in frame \(S\). the length of the plank is now\(L=L_{0} \sqrt{1-\frac{v^{2}}{c^{2}} \cos \theta_{0}}\) and the angle it makes with the \(x\) -axis is $$ \theta=\tan ^{-1}\left(\gamma_{v} \tan \theta_{0}\right) $$.

Short Answer

Expert verified
The length and the angle of the plank as perceived by the observer in frame \(S\), after the sled starts moving are given by \(L = L_{0} \sqrt{1-\frac{v^{2}}{c^{2}} cos^2 \theta_0}\) and \(\theta = \tan^{-1}(\gamma_v \tan \theta_{0})\) respectively.

Step by step solution

01

Identify the Given Information

Initial parameters are given as follows: the plank's resting length is \(L_0\), the speed of the sled is \(v\), and the angle that the plank makes with the x-axis is \(\theta_0\). The task is to find the length of the plank and the angle it makes with the x-axis from the perspective of an observer in frame \(S\).
02

Apply the Formula for Length Contraction

As per the principle of length contraction in special relativity, the length of the plank as measured by the observer in stationary frame \(S\) after the sled starts moving is given by the formula \(L = L_{0} \sqrt{1-\frac{v^{2}}{c^{2}} cos^2 \theta_0}\). This formula accounts for the fact that length contraction happens only along the direction of motion (\(cos^2 \theta_0\) part).
03

Determine the Angle

Next, we need to calculate the angle the plank makes with the x-axis after the sled starts moving. This is given by \(\theta = \tan^{-1}(\gamma_v \tan \theta_{0})\), where \(\gamma_v = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\) is the Lorentz factor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special relativity is a theory proposed by Albert Einstein that revolutionized our understanding of space and time. One of its key ideas is that the laws of physics are the same for all observers, regardless of their relative motion. This means, among other things, that neither time nor space are absolute. Instead, they are interconnected in what we call spacetime.

A fascinating consequence of special relativity is the phenomenon known as length contraction. When an object moves at a high velocity compared to the speed of light, it appears shorter in the direction of motion to a stationary observer. This effect becomes significant as the object approaches the speed of light.

For example, if a sled with a plank is moving quickly, an observer at rest would perceive the plank's length differently than an observer moving with the sled. This can be seen through special relativity equations, which show how significantly the length shortens based on speed and direction.
Lorentz Factor
The Lorentz factor, often denoted as \( \gamma \), is a crucial component of special relativity. It quantifies the amount of change in time and space dimensions for an object moving at relativistic speeds.

The Lorentz factor is defined as:\[\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}\]where \( v \) is the velocity of the moving object, and \( c \) is the speed of light.
  • As an object’s speed \( v \) approaches the speed of light \( c \), \( \gamma \) increases dramatically. This means greater time dilation and length contraction occur.
  • If \( v = 0 \), \( \gamma \) equals 1, signifying no relativistic effects.
In our scenario, the plank on the sled experiences these changes due to its motion. Consequently, the observer at rest uses the Lorentz factor to calculate the modified angle of the plank concerning the x-axis. The angle transformation is key, as the Lorentz factor affects how angles are perceived in a moving frame.
Angle Transformation
Angle transformation in the context of special relativity refers to how angles change when observed from different frames of reference. When analyzing the length of a moving plank, not only does its length contract, but the angle it makes with an axis transforms as well.

In our example, the original angle of the plank \( \theta_0 \) changes when the sled starts moving. For an observer at rest, this new angle \( \theta \) can be found using the formula:\[\theta = \tan^{-1}(\gamma_v \tan \theta_0)\]where \( \gamma_v \) is the Lorentz factor.
  • This transformation shows that the angle depends on both the original angle and the velocity of the sled.
  • As the speed increases and \( \gamma_v \) becomes larger, even small initial angles \( \theta_0 \) can lead to significant perceived changes.
Understanding angle transformation enriches our comprehension of how velocity affects not just an object's size, but also its orientation as observed from different frames.

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Most popular questions from this chapter

Appearing in the time-dilation and length-contraction formulas, \(\gamma_{y}\) is a reasonable measure of the size of relativistic effects. Roughly speaking, at what speed would observations deviate from classical expectations by \(1 \% ?\)

A point charge \(+q\) rests halfway between two steady streams of positive charge of equal charge per unit length \(\lambda\), moving opposite directions and each at \(c / 3\) relative to point charge. With equal electric forces on the point charge, it would remain at rest. Consider the situation from a frame moving right at \(c / 3\). (a) Find the charge per unit length of each stream in this frame. (b) Calculate the electric force and the magnetic force on the point charge in this frame, and explain why they must be related the way they are. (Recall that the electric field of a line of charge is \(\lambda / 2 \pi \varepsilon_{0} r\), that the magnetic field of a long wire is \(\mu_{0} I / 2 \pi r\), and that the magnetic force is \(q \mathbf{v} \times \mathbf{B}\). You will also need to relate \(\lambda\) and the current \(L\).)

In a television picture tube, a beam of electrons is sent from the back to the front (screen) by an electron gun. When an electron strikes the screen, it causes a phosphor to glow briefly. To produce an image across the entire screen. the beam is electrically deflected up and down and left and right. The beam may sweep from left to right at a speed greater than \(c\). Why is this not a violation of the claim that no information may travel faster than the speed of light?

You are in a bus traveling on a straight road ar \(20 \mathrm{~m} / \mathrm{s}\). As you pass a gas station, your clock and a clock in the station read precisely 0. You pass another gas station \(900 \mathrm{~m}\) farther down the road. ( In the frame of reference of the gas stations. all gas station clocks are synchronized.) (a) As you pass the second station. do you find its clock to be ahead of, or behind your own clock, and (b) by how much?

If an object actually occupies less space physically when moving, it cannot depend on the direction we define as positive. As we know, an object aligned with the direction of relative motion is contracted whether it is fixed in frame \(S\) and viewed from \(S^{\prime}\), or the other way around. Use this idea to argue that distances along the \(y\) - and \(y^{\prime}\) -axes cannot differ at all. Consider a post of length \(L_{0}\) fixed in frame \(S\), jutting up from the origin along the \(+y\) -axis, with a saw at the top poised to slice off anything extending any higher in the passing frame \(S\). Also consider an identical post fixed in frame \(S\). What happens when the origins cross?

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