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Explain to your friend, who is willing to accept that light moves at the same speed in any frame, why clocks on a passing train are not synchronized. If it helps, assume that Anna is at the middle of the train.

Short Answer

Expert verified
Due to the relativity of simultaneity and the constancy of the speed of light, clocks on a moving train appear desynchronized to an external observer, although they are synchronized from the perspective of someone on the train. As an observer, you first see the light emitted from the rear clock due to the train's motion, and then from the front clock, leading to an apparent lack of synchronization.

Step by step solution

01

Understand the scenario

Imagine a scenario where a train is moving past you and Anna is located exactly in the middle of this train. Anna controls two clocks: one at the rear of the train and the other at the front. From Anna's frame of reference, which is the train, both clocks are synchronized, meaning they both tell the same time at the same moment.
02

Understand the observer's perspective

As an observer standing on a platform as the train moves past, you're viewing this situation from a different frame of reference. The principle of relativity states that the laws of physics - and thus the speed of light - are the same in all inertial frames. Hence, the speed of light, \( c \), remains constant whether you're on the train or standing still on the platform.
03

Apply the principle of simultaneity

When the light from both the front and rear clocks reaches your eyes, due to the train's motion, you actually see the light from the rear clock first before the light from the front clock. This is because the rear clock is moving towards you, reducing the distance light needs to travel compared to when it was emitted. Conversely, the front clock moves away from you, increasing the distance the light must travel. Given that the speed of light is constant, this results in a delay of the light reaching you from the front clock.
04

Explain the lack of synchronization

Due to this discrepancy in when the light from the two clocks reaches you, it seems as if the two clocks are not synchronized from your point of view, even though they are synchronized according to Anna. This phenomenon is referred to as 'relativity of simultaneity' and is a direct consequence of the constancy of the speed of light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frame of Reference
Understanding the concept of a frame of reference is crucial when delving into physics, especially in discussions surrounding relativity. It is essentially a viewpoint or a perspective from which an observer measures positions and movements. A frame of reference can be stationary, like a person standing on a platform, or it can be moving, like a passenger aboard a train.

With relativity of simultaneity, the notion of 'now' or 'simultaneous' becomes relative to the observer's frame of reference. If you're on the moving train, you share a frame of reference with Anna, and the train's clocks seem synchronized. However, an observer on the platform has a different frame of reference and perceives the train's clocks differently.

Imagine watching a ballet from the front row, then moving to a balcony seat. The dance moves haven't changed, but your perspective has shifted, altering your experience and interpretation of the performance. In physics, this change of perspective helps explain why the same event can be perceived differently from distinct frames of reference.
Speed of Light
The speed of light, designated by the constant 'c', has a value of approximately 299,792 kilometers per second in a vacuum. It's not just a speed limit for light, but for all forms of energy, matter, and information in the universe. Within the context of special relativity, this speed takes on profound implications.

According to physics, nothing in the universe can travel faster than light. No matter what frame of reference an observer is in, light's speed remains steadfast. This constancy underpins many of special relativity's counterintuitive predictions, including the relativity of simultaneity. Whether you're speeding along in a train or chilling on a bench, a beam of light will move at 'c' with respect to you. Now, that's consistency on a cosmic scale!
Special Relativity
Special relativity, introduced by Albert Einstein in 1905, revolutionized our understanding of space, time, and how they interconnect. This theory is based on two postulates: The laws of physics are the same for all observers in inertial (non-accelerating) frames of reference; and, as just discussed, the speed of light in a vacuum is the same for all observers, regardless of their relative motion or the source's motion.

From these postulates, groundbreaking insights emerged, including the notorious E=mc² equation and the dilation of time. The latter has direct implications on the synchronization of clocks, as it dictates that moving clocks tick slower compared to those at rest — a real-time twister for the minds of many. Special relativity ensures that your motion can literally change the passage of time, but only when relative to other observers. It's all about perspective.
Time Dilation
Time dilation is a consequence of the finite speed of light and the tenets of special relativity. It refers to the difference in elapsed time as measured by two observers, due in part to their relative velocity. The faster an object moves, the more significant this effect becomes.

To understand time dilation, consider a light clock — a hypothetical clock that measures time by the bouncing of light between two mirrors. If the clock is stationary, light travels directly up and down between the mirrors. However, if it's moving quickly (like on a train), light takes a diagonal path, resulting in a longer journey between ticks. This longer path means that fewer 'ticks' will happen on a quickly moving clock from the perspective of a stationary observer.

For an observer onboard the train (i.e., moving with the clock), time seems to pass normally. But an external, stationary observer would see the on-board clock ticking more slowly — thus, two observers in different frames of reference perceive time differently. Keep in mind, though, for everyday speeds, this effect is too minuscule to notice; it becomes significant only at relativistic speeds, a sizable fraction of the speed of light.

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Most popular questions from this chapter

In the collision shown, energy is conserved. because both objects have the same speed and mass after as before the collision. Since the collision merely reverses the velocities, the final (total) momentum is opposite the initial. Thus, momentum can be conserved ooly if it is zero. (a) Using the relativistically correct expression for momentum, show that the total momentum is zero that momentum is conserved. (Masses are in arbitrary units.) (b) Using the relativistic velocity transformation, find the four velocities in a frame moving to the right at \(0.6 c\) (c) Verify that momentum is conserved in che new frame.

You stand at the center of your. \(100 \mathrm{~m}\) spaceship and watch Anna's identical ship pass at \(0.6 \mathrm{c} .\) At \(t=0\) on your wristwatch. Anna, at the center of her ship, is directly across from you and her wristwatch also reads \(0 .\) (a) A friend on your ship, \(24 \mathrm{~m}\) from you in a direction toward the tail of Anna's passing ship, looks at a clock directly across from him on Anna's ship. What does it read? (b) Your friend now steps onto Anna's ship. By this very act, he moves from a frame where Anna is one age to a frame where she is another. What is the difference in these ages? Explain. (Hint: Your friend moves to Anna's frame, where the time is whatever the clock at the location reads.) (c) Answer parts (a) and (b) for a friend \(24 \mathrm{~m}\) from you but in a direction toward the front of Anna's passing ship. (d) What happens to the reading on a clock when you accelerate toward it? Away from it?

You are on a high-speed train. traveling at a decent clip: \(0.8 c\). On the ground are two signal stations 5 km per. each with a status-reporting sign, which always give simultaneous reports. Ar precisely noon on the train's clocks. the conductor at the front of the train passes one station and sees a sign reading "All Clear," and another employee at the back passes the other station and sees a sign reading "Severe Electrical Storms Reported! Slow to \(0.1 c ! "\) (a) How long is the train? (b) Should it slow down? (c) Suppose that both reporting signs display the time very precisely, updated every microsecond. By how much would the two observed time readings differ, if at all?

Appearing in the time-dilation and length-contraction formulas, \(\gamma_{y}\) is a reasonable measure of the size of relativistic effects. Roughly speaking, at what speed would observations deviate from classical expectations by \(1 \% ?\)

A meterstick is glued to the wall with its \(100 \mathrm{~cm}\) end farther to the right, in the positive direction. It has a clock at its center and one on each end. You walk by A meterstick is glued to the wall with its 100 em end farther to the right, in the positive direction. It has a clock at its center and one on each end. You walk by the meterstick in the positive direction at speed \(v\). (a) When you reach the center clock, it reads \(0 .\) What do the other two read at this instant in your frame. (b) You instantly reverse direction. The clock at the center is still reading 0 and so is yours. What do the others read? (c) How does this relate to the twin paradox?

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