Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Oxygen- \(19 \beta^{-}\) decays. What is the daughter nucleus, and what may be said of the kinetic energy of the emitted \(\beta^{-}\) particle?

Short Answer

Expert verified
The daughter nucleus is fluorine-19 (F(9,19)). The kinetic energy of the emitted beta particle cannot be determined from the information provided, but it is variable and carries away the difference in energy between the parent and daughter nucleus.

Step by step solution

01

Write down the nuclear equation for beta-minus decay

In the general equation for beta-minus decay, X(Z,A) -> Y(Z+1,A) + e− + \overline{v}e, replace X(Z,A) with the oxygen-19 nucleus. Oxygen-19 is written as O(8,19). The resulting equation is: O(8,19) -> Y(Z+1,A) + e− + \overline{v}e.
02

Identify the daughter nucleus

In the nuclear equation, Z is increased by 1 while A remains constant. Thus, the daughter nucleus has 9 protons and the same total number of nucleons, 19. The nucleus with atomic number 9 is fluorine. Hence, Y(Z+1,A) is replaced with F(9,19) and the complete nuclear equation is: O(8,19) -> F(9,19) + e− + \overline{v}e.
03

Determine the kinetic energy of the emitted beta particle

In any nuclear decay, energy is conserved. The kinetic energy of the emitted beta particle comes from the conversion of the mass of the neutron into energy according to Einstein's equation E=mc^2. However, the actual calculation of this energy requires knowledge of the masses of the neutron, proton, electron and anti-neutrino, which are not given in the problem. Therefore, it's not possible to calculate the kinetic energy of the beta particle from the information provided. In general however, it can be said that the kinetic energy of the emitted beta particle is variable and carries away the difference in energy between the parent nucleus and daughter nucleus so as to conserve energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Nuclear Equations
Nuclear equations are like the math of particles! They help us understand how elements change during radioactive decay. When beta-minus decay happens, a neutron transforms into a proton, increasing the element’s atomic number by one. The nucleus loses a beta particle (an electron) and an antineutrino. The nuclear equation for beta-minus decay from Oxygen-19 looks like this:
  • For Oxygen-19: \(\text{O}(8,19) \to \text{F}(9,19) + e^- + \overline{v}_e\)
The key is that the atomic mass (A) stays the same, while the atomic number (Z) goes up by one. This change results in the formation of a new element, which leads us to our next concept.
Identifying the Daughter Nucleus
The daughter nucleus is the new nucleus formed after radioactive decay. In the case of Oxygen-19, it turns into Fluorine-19. But why? In beta-minus decay, like our example, the atomic number increases by one, but the mass number remains constant.
  • Oxygen-19 starts with 8 protons. After decay, it has 9 protons - making it Fluorine-19!
We identify the daughter nucleus by knowing the new element based on the updated atomic number. So, every time a beta-minus decay happens, you can spot the daughter nucleus by looking one element up on the periodic table.
Kinetic Energy of Beta Particles
The kinetic energy of beta particles is a key part of beta decay. But what is it, and why does it matter? When an electron (beta particle) and an antineutrino are emitted, energy is released. This energy is shared between the beta particle and the antineutrino, which means beta particles have variable kinetic energy.
  • The energy source is the mass difference between the parent and daughter nucleus, as described by Einstein's equation \(E = mc^2\).
  • Even though exact calculations need more data, we know this energy helps preserve the balance (or conservation) of energy in the decay.
Understanding the kinetic energy helps scientists and students alike figure out the behavior of beta particles in various materials.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The vast majority of measured nuclear spins are fairly small, between zero and nine times \(\frac{1}{2} h\). More to the point, nuclear spin does not unif ormly increase with \(A\) Argue that if the assumptions in the shell model are valid, then these observations are not unexpected.

In both D-D reactions in equation \((11-18)\). two deuterons fuse to produce nwo particles, a nucleus of \(A=3\) and a free nucleon. Mass decreases because the binding energy of the \(A=3\) nucleus is greater than the combined binding cnergies of the two deuterons. The binding energy of haliam- 4 is even greater still. Why can't the deuterons simply fuse into a helium -4 nucleus and nothing else? Why must muluple particles be produced?

Calculate the binding energy per nucleon of carbon-12.

Equation \((9-42)\) gives the Fermi energy for a collection of identical fermions packed into the lowest energies allowed by the exclusion principle. Argue that if applied to neutrons or protons (ignoring their repulsion) in a nucleus, the equation suggests that the Fermi energy is roughly the same for all nuclei. Making the rough approximation that the spacing between quantum levels is a constant in a given nucleus, argue that this spacing should vary from one nucleus to another in proportion to \(A^{-1}\)

The half Life \(T_{1 \Omega}\) is not the average lifetime rof a radioactive nucleus. We find the average lifetime by multiplying 8 by the probability per unit tinie \(P(t)\) that the nucleus will "live" that long, then integrating over all time. (a) Show that \(P(t)\) should be given by \(\lambda e^{-A \text { 1. }}\). Hint: What must be the total probability?) (b) Show that \(r=T_{1 \Omega} / \ln 2\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free