When electrons cross from the \(\mathrm{n}\) -type to the p-type to equalize the
Fenni energy on both sides in an unbiased diode, they leave the \(n\) -type side
with an excess of positive charge and give the p-type side an excess of
negative. Charge layers oppose one another on either side of the depletion
zone, producing, in essence, a capacitor, which harbors the so-called built-in
electric field. The crossing of the electrons to equalize the Fenni energy
produces the dogleg in the bands of roughly \(E_{\text {mag, }}\) and the
corresponding potential difference is \(E_{\text {gap }}\) /e. The depletion
zone in a typical diode is \(1 \mu \mathrm{m}\) wide, and the band gap is \(1.0
\mathrm{eV}\), How large is the buill-in electric field?