Chapter 10: Problem 33
In Section 10.2. we discussed two-lobed \(p_{\text {re }} p_{\text {s }}\) and \(p_{z}\) states and four-lohed hybrid \(s p^{3}\) states. Another kind of hybrid state that sticks out in just one direction is the sp. formed from a single \(p\) state and an \(s\) state. Consider an urbitrary combination of the \(2 s\) state with the \(2 p_{x}\) state. Let us represent this by \(\cos \tau \psi_{2.0 .0}+\sin T \psi_{2.1 .0}\) (The trig factors ensure norinalization. In carrying out the integral, crow terms integrate to \(0 .\) leaving \(\cos ^{2}+\int\left|\psi_{2,0,0}\right|^{2} d b^{\prime}+\sin ^{2} \tau \int\left|\psi_{21,0}\right|^{2} d V\). which is \(\left.1 .\right)\) (a) Calculate the probability that an electron in such a state would be in the \(+z\) -hemisphere. (Nore: Here. the cross tems do nor integrate to \(0 .\) ) (b) What value of \(r\) leads to the maximum probability. what is the value of the maximum probability, and what is the cotresponding ratio of \(\psi_{2,0.0}\) to \(\phi_{2,1,0} ?\) (c) Using a computer, make a density (shading) plot of the probability density - density versus \(r\) and \(\theta\) for the \(r\) -value found in part (b).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.