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Discuss qualitatively the motion of the atoms in a block of steel that falls onto another steel block. Why and how do large-scale vibrations damp out?

Short Answer

Expert verified

When the atoms in the steel block fall into another steel block, then the particles mainly behave in the waveform. The large-scale vibrations damp out through the inner friction which mainly translates into heat. A small amount of dissipation may turn into radiation and sound.

Step by step solution

01

Significance of the translational motion and the law of vibration

The atoms can easily move from one position to another position which is referred to as the translational motion of the atoms.

The law of vibration illustrates that every single particle in this universe is in a constant movement state.

The motion of the atoms can be predicted by the translational motion and the law of vibrations gives the reason for the damping out of the vibrations.

02

Determination of the atom’s motion and damping out the vibrations

As a steel block is treated as a rigid object, hence it is a multiparticle system. However, while collision, the particles mainly acquire kinetic energy and transfer the energy into a waveform that eventually creates vibration.

As materials have a type of damping effect, hence, the kinetic energy gets transformed into heat for the friction that exists between the materials. However, due to the loss of energy, the amplitude of the wave decreases with time. Hence, the property of the materials for which the oscillations are damped due to the inner friction is mainly called hysteretic damping.

Hysteretic damping is mainly used for dissipating energy. A small amount of energy may be dissipated in radiation and sound form.

Thus, when the atoms in the steel block fall into another steel block, then the particles mainly behave in the waveform. The large-scale vibrations damp out through the inner friction which mainly translates into heat. A small amount of dissipation may turn into radiation and sound.

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Most popular questions from this chapter

A rod of length Land negligible mass is attached to a uniform disk of mass Mand radius R (Figure 9.64). A string is wrapped around the disk, and you pull on the string with a constant force F . Two small balls each of mass mslide along the rod with negligible friction. The apparatus starts from rest, and when the center of the disk has moved a distance d, a length of string shas come off the disk, and the balls have collided with the ends of the rod and stuck there. The apparatus slides on a nearly frictionless table. Here is a view from above:

(a) At this instant, what is the speed vof the center of the disk? (b) At this instant the angular speed of the disk isฯ‰ . How much internal energy change has there been?

By calculating numerical quantities for a multiparticle system. One can get a concrete sense of the meaning of the relationships pโ†’sys=Mtotvโ†’CMand Ktot=Ktrans+Krel. Consider an object consisting of two balls connected by a spring, whose stiffness is 400 N/m. The object has been thrown through the air and is rotating and vibrating as it moves. At a particular instant, the spring is stretched 0.3m, and the two balls at the ends of the spring have the following masses and velocities: 1:5kg.(8,14,0)m/s2:3kg(-5,9,0)m/s

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Consider the voyage to the Moon that you studied in Chapter 3. Would it make any difference, even a very tiny difference, whether the spacecraft is long or short, if the mass is the same? Explain briefly.

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