Question

A roughly spherical asteroid has a mass ofand a radius of 270 km. (a) What is the value of the constant g at a location on the surface of the asteroid? (b) What would be the magnitude of the gravitational force exerted by the asteroid on a 70 kg astronaut standing on the asteroid’s surface? (c) How does this compare to the gravitational force on the same astronaut when standing on the surface of the Earth?

Short answer

(a) The value of the $g$at a location on the surface of the asteroid is$284\backslash mathrm\{~N\}/\backslash mathrm\left\{kg\right\}$

(b) The Magnitude of the gravitational force on astronaut on the surface of the asteroid is$19.88\mathrm{N}$

(c) The result states that the gravitational force on asteroid is very small compared to that on surface of the earth.

Step-by-step solution

 Identification of Data.

The mass of the asteroid is$m_a=3.11\times {10}^{20}\mathrm{kg}$

The Radius of the asteroid is,$r=270\mathrm{km}$

The mass of astronaut is,$m=70\mathrm{kg}$

Concept of gravity

Gravity is a force that pulls items together over a long distance by acting on their mass.

Gravity is the curvature of spacetime driven by mass energy, which governs mass-energy paths (equations of motion).

(a) Determination of the value of constant g.

(a)

Acceleration due to gravity on asteroid is,

$g=\frac{G{m}_{\mathrm{a}}}{r^2}$

Here, $G$is the universal gravitational constant whose value is given by $6.673\times {10}^{-11}\mathrm{N}·{\mathrm{m}}^2/{\mathrm{kg}}^2,m_{\mathrm{s}}$is the mass of the asteroid, $r$is the radius.

Substitute values in the above equation.

$\backslash begin\left\{aligned\right\}g\&=\backslash frac\{6.673\backslash times10^\{-11\}\backslash mathrm\{~N\}\backslash cdot\backslash mathrm\{m\}^\{2\}/\backslash mathrm\{kg\}^\{2\}\backslash left(3.11\backslash times10^\left\{20\right\}\backslash mathrm\{~kg\}\backslash right\left)\right\}\left\{\right(270\backslash mathrm\{~km\})^\{2\left\}\right\}\backslash \backslash \&=\backslash frac\{6.673\backslash times10^\{-11\}\backslash mathrm\{~N\}\backslash cdot\backslash mathrm\{m\}^\{2\}/\backslash mathrm\{kg\}^\{2\}\backslash left(3.1\backslash times10^\left\{20\right\}\backslash mathrm\{~kg\}\backslash right\left)\right\}\{\backslash left[270\backslash mathrm\{~km\}\backslash left(\backslash frac\{1000\backslash mathrm\{~m\}\left\}\right\{1\backslash mathrm\{~km\}\}\backslash right)\backslash right]^\{2\left\}\right\}\backslash \backslash \&=0.284\backslash mathrm\{~N\}/\backslash mathrm\left\{kg\right\}\backslash end\left\{aligned\right\}$

Thus, the value of the $g$at a location on the surface of the asteroid is $284\backslash mathrm\{~N\}/\backslash mathrm\left\{kg\right\}$

Determination of the value of gravitational force on astronaut.

(b)

The gravitational force on an astronaut of mass $m$is given by.

$F=mg$

Here, $m$is the mass, and $g$is the acceleration due to gravity.

Substitute values in the above equation.

$\backslash begin\left\{aligned\right\}F\&=70\backslash mathrm\{~kg\}(0.284\backslash mathrm\{~N\}/\backslash mathrm\{kg\left\}\right)\backslash \backslash \&=19.88\backslash mathrm\{~N\}\backslash end\left\{aligned\right\}$

Thus, the force on astronaut is$19.88\mathrm{N}$

step 5  (c) Determination the gravitational force on the same astronaut when standing on the surface of Earth.

(c)

The gravitational force on the astronaut is given by,

$F^{\text{'}}=m{g}^{\text{'}}$

Here, $m$is the mass and $g$is the acceleration due to gravity on the surface of the earth.

Substitute values in the above equation.

$\backslash begin\left\{aligned\right\}F\&=70\backslash mathrm\{~kg\}(9.8\backslash mathrm\{~N\}/\backslash mathrm\{kg\left\}\right)\backslash \backslash \&=686\backslash mathrm\{~N\}\backslash end\left\{aligned\right\}$

Thus, the result states that the gravitational force on asteroid is very small compared to that on surface of the earth.