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An electron is moving with a speed v in the plane of the page (Figure 20.81), and there is a uniform magnetic field Binto the page throughout this region; the magnetic field is produced by some large coils that are not shown. Draw the trajectory of the electron, and explain qualitatively.

Short Answer

Expert verified

The trajectory of the electron is as follows:

Step by step solution

01

Given data

Speed of the electron isv .

Magnetic field in the region isB .

02

Magnetic force

Magnetic force on a moving charge is the product of the magnitude of the charge and the cross product of the velocity vector and the magnetic field.

03

Determination of the trajectory of the electron

The cross product of the velocity and the magnetic field will be on the plane of the paper perpendicular to the velocity. As the particle turns due to this force, the direction of force turns too. The particle thus follows a circular path on the plane. Since the charge of the electron is negative, the circle will be clockwise. The trajectory will be as follows:

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Most popular questions from this chapter

In Figure 20.115 two long straight wires carrying a large conventional current I are connected by one-and-a-quarter turns of wire of radius R. An electron is moving to the right with speed v at the instant that it passes through the center of the arc. You apply an electric field Eat the center of the arc in such a way that the net force on the electron at this instant is zero. (You can neglect the gravitational force on the electron, which is easily shown to be negligible, and the magnetic field of the coil is much larger than the magnetic field of the Earth.)

Determine the direction and magnitude of the electric field . Be sure to explain your work fully; draw and label any vectors you use.

:In Figure 20.121 a bar 11 cm long with a rectangular cross section 3 cm high and 2 cm deep is connected to a 1.2 V battery and an ammeter. The resistance of the copper connecting wires and the ammeter, and the internal resistance of the battery, are all negligible compared to the resistance of the bar.

Using large coils not shown on the diagram, a uniform magnetic field of 1.8 T was applied perpendicular to the bar (out of the page, as shown). A voltmeter was connected across the bar, with the connections across the bar carefully placed directly across from each other.

The mobile charges in the bar have charge +e, their density is 7×1023/m3, and their mobility is 3×105(m/s)/(V/m).

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A copper wire with square cross section carries a conventional current I to the left (as in Figure 20.83). There is a magnetic field B perpendicular to the wire. Describe the direction of E, the transverse electric field inside the wire due to the Hall effect, and explain briefly.

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