Question

The electron current in a horizontal metal wire is$3.7\times {10}^{18}\mathrm{electrons}$, and the electrons are moving to the right. What are the magnitude and direction of the conventional current?

Short answer

0.6 A, towards left

Step-by-step solution

Given Data

Electron current =$3.7\times {10}^{18}electron/s$

Formula used

Electron passing through the wire per second is the electron current i

$\mathrm{i}=\frac{1}{\left|\mathrm{q}\right|}$

Where, I is Conventional current

Calculation of conventional current

$$\begin{gathered} I=i\left|q\right| \\ =3.7\times {10}^{18}\left|-1.6\times {10}^{-19}\right| \\ =0.6A \end{gathered}$$

Direction of the conventional current is towards left.