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300gof water whose temperature is25oCare added to a thin glass containing 800 g of water at20oC(about room temperature). What is the final temperature of the water? What simplifying assumptions did you have to make in order to determine your approximate result?

Short Answer

Expert verified

The final temperature of the water after adding it to thin glass is 21.36°C.

The simplifying assumption which helped in determining the approximate result is the heat transfer through the glass is negligible.

Step by step solution

01

Define the energy Principle

The free energy principle defines how non-equilibrium steady-states are maintained in living and non-living systems by restricting their states to a minimal number. It establishes that systems minimise a free energy function of their internal states, implying hidden states in the environment.

02

Calculation of final temperature of water

Using the Energy Principle, determine the water's ultimate temperature. Subscriptis used to indicate the300g of water and subscript 2to designate the water already in the glass ( 800g).

Take the sum of both the energiesΔE1andΔE2

ΔE1+ΔE2=0m1CH20(TfT1,i)+m2CH20(TfT2,i)=0

Here Solve the equation for Tf.

Tf=m1T1,i+m2T2,im1+m2=(300g)(25°C)+(800g)(20°C)300g+800g=21.36°C

03

Assumptions made to approximate result

The following assumptions had to be made in order to calculate the final temperature:

  • As the glass is so thin, heat transmission between water and the glass is minimal.
  • No heat is sent to the environment.
  • Enough time has passed for the ultimate temperature to be attained.

Therefore, the final temperature of the water is21.36°C and the assumption made is heat transfer only occurs between the two masses of water.

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