Question

In order to calculate the number of ways of arranging a given amount of energy in a tiny block of copper, the block is modeled as containing $\mathbf{8}\mathbf{.}\mathbf{7}\mathbf{\times }{\mathbf{10}}^{\mathbf{5}}$independent oscillators. How many atoms are in the copper block?

Short answer

$2.9\times {10}^5$atoms are in the copper block.

Step-by-step solution

Given data

The block is containing $8.7\times {10}^5$independent oscillators.

Solution

Each atom can have 3 independent oscillations.

Number of atoms= $\frac{\mathrm{Number}\mathrm{of}\mathrm{oscillators}}{3}$

= $\frac{8.7\times {10}^5}{3}$

= $2.9\times {10}^5$