Question

If the magnetic field in a particular pulse has a magnitude of $\mathbf{1}\mathbf{x}{\mathbf{10}}^{-\mathbf{5}}\mathbf{T}$ (comparable to the Earth's magnetic field). What is the magnitude of the associated electric field?

Short answer

The magnitude of the associated electric field is$3000 \text{V/m}$

Step-by-step solution

Identification of given data

Magnitude of magnetic field$B=1\times {10}^{-5} \text{T}$

Concept of Ampere’s law

It states that the pulse of the electric field and magnetic field is travelling through space with speed of light. It is given as

$E=cB$ …(i)

Where, $E$is the electric field, $B$is the magnetic field and $c$ is the speed of light

Determining the magnitude of the associated electric field

Substituting all the values in equation (i)

$$\begin{gathered} E=\left(3\times {10}^8 \text{m/s}\right)\times \left(1\times {10}^{-5} \text{T}\right) \\ =3000 \text{V/m} \end{gathered}$$

Hence the magnitude of the associated electric field is$3000 \text{V/m}$