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Chapter 16: Q4Q (page 662)

What is the difference between electric potential energy and electric potential?

Short Answer

Expert verified

It can be concluded that the electric potential energy is associated to two or more particles together, whereas the electric potential is tied to one particle.

Step by step solution

01

Concept/Significance of electric potential energy

It is a potential energy associated with the configuration of a certain collection of point charges within a defined system as a result of conservative coulomb force.

02

Determination of differences between electric potential energy and electric potential.

The potential energy means each particle has its own energy, but to keep two particles or more together in a system, we need energy, this energy is the electric potential energy.

Whereas, the electric potential is the amount of energy per charge, so it is related to one particle while the electric potential energy is related to two or more particles together.

Thus, it can be concluded that the electric potential energy is associated to two or more particles together, whereas the electric potential is tied to one particle.

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Most popular questions from this chapter

Question: If the kinetic energy of an electron is $4.4 \times 10^{- 18} J$ , what is the speed of the electron? You can use the approximate (non relativistic) equation here.

How much work is required to move a proton and an electron at rest a distance $3 \times 10^{- 8} m$ apart to be at rest a distance $7 \times 10^{- 8} m$ apart?

For a path starting at B and going to A (Figure 16.9), calculate (a) the change in electric potential, (b) the potential energy change for the system when a proton moves from B to A, and (c) the potential energy change for the system when an electron moves from B to A. For a path starting at B and going to C, calculate (d) the change in electric potential, (e) the potential energy change for the system when a proton moves from B to C, and (f) the potential energy change for the system when an electron moves from B to C.

Location A is a distance d from a charged particle. Location B is a distance 2d from the particle. Which of the following statements are true? It may help to draw a diagram. (1) If the charge of the particle is negative, $V_{B} - V_{A}$ is negative. (2) If the charge of the particle is positive, $(V_{A} < V_{B})$ . (3) If $V_{B} < V_{A}$ , we know that the particle must be positive. (4) $V_{B} < V_{A}$ , regardless of the sign of the charge of the particle. (5) The sign of $(V_{B} - V_{A})$ does not give us any information about the sign of the charge of the particle.

Locations $A = < a, 0, 0 > and B = < b, 0, 0 >$ are on the +x axis, as shown in Figure 16.61. Four possible expressions for the electric field along the x axis are given below. For each expression for the electric field, select the correct expression (1–8) for the potential difference $V_{A} - V_{B}$ . In each case K is a numerical constant with appropriate units.

$(a) \vec{E} = < \frac{K}{x^{2}}, 0, 0 > (b) \vec{E} = < \frac{K}{x^{3}}, 0, 0 > (c) \vec{E} = < \frac{K}{x}, 0, 0 > (b) \vec{E} = < Kx, 0, 0 > (1) V_{A} - V_{B} = 0 (2) V_{A} - V_{B} = K (a - b) (3) V_{A} - V_{B} = K (\frac{1}{a} - \frac{1}{b}) (4) V_{A} - V_{B} = K (\frac{1}{a^{3}} a - \frac{1}{b^{3}} b) (5) V_{A} - V_{B} = \frac{1}{2} K (b^{2} - a^{2}) (6) V_{A} - V_{B} = K In (\frac{b}{a}) (7) V_{A} - V_{B} = K (a^{3} - b^{3}) (8) V_{A} - V_{B} = \frac{1}{2} K (\frac{1}{a^{2}} - \frac{1}{b^{2}})$

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