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A large positive charge pulls on a distant electron. How does the net force on the electron change if a slab of glass is inserted between the large positive charge and the electron? Does the net force get bigger, smaller, or stay the same? Explain, using only labeled diagrams. (Be sure to show all the forces on the electron before determining the net force on the electron, not just the force exerted by the large positive charge. Remember that the part of the net force on the electron contributed by the large positive charge does not change when the glass is inserted: the electric interaction extends through matter.)

Short Answer

Expert verified

The net force on the electron will become smaller.The force on the electron in the presence of a glass slab decreases due to an opposing force (field), which is executed due to the polarization of glass.

Step by step solution

01

Concept

The force between two charges depends upon the charges, the distance between them, and the medium they are in. If the medium between them changes, the force will also change accordingly.

02

The change in the net force

Case 1 : In the air (vacuum)

The net force between charge Q and electron e can be written as when they are at a distance r from each other as,

F1=14πε0Qer2

Here ε0is the permittivity of free space.

Case 2: The slab of glass

The net force between charge Q and electron e can be written as when they are at a distance r from each other when there is a slab of glass inserted as,

F2=F1-Fp=14πε0εrQer2

HereFpis the force opposite to the attraction force due to the polarization of the slab of glass and εr is the relative permittivity due to the glass.

The only difference is the factor εr in both cases.

Thus, the net force on the electron will become smaller.The force on the electron in the presence of a glass slab decreases due to an opposing force (field), which is executed due to the polarization of glass.

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Most popular questions from this chapter

Try rubbing a plastic pen through your hair, and you’ll find that you can pick up a tiny scrap of paper when the pen is about one centimeter above the paper. From this simple experiment you can estimate how much an atom in the paper is polarized by the pen! You will need to make several assumptions and approximations. Hints may be found at the end of the chapter. (a) Suppose that the center of the outer electron cloud (q=-4e) of a carbon atom shifts a distance s when the atom is polarized by the pen. Calculate s algebraically in terms of the charge Q on the pen. (b) Assume that the pen carries about as much charge Q as we typically find on a piece of charged invisible tape. Evaluate s numerically. How does this compare with the size of an atom or a nucleus? (c) Calculate the polarizability αof a carbon atom. Compare your answer to the measured value of 1.96×10-40C.m/(N/C)(T. M. Miller and B. Bederson, “Atomic and molecular polarizabilities: a review of recent advances,” Advances in Atomic and Molecular Physics, 13, 1–55, 1977).(d) Carefully list all assumptions and approximations.

You run your finger along the slick side of a positively charged tape, and then observe that the tape is no longer attracted to your hand. Which of the following are not plausible explanations for this observation? Check all that apply. (1) Sodium ions (Na+) from the salt water on your skin move onto the tape, leaving the tape with a zero (or very small) net charge. (2) Electrons from the mobile electron sea in your hand move onto the tape, leaving the tape with a zero (or very small) net charge. (3) Chloride ions (CI-) from the salt water on your skin move onto the tape, leaving the tape with a zero (or very small) net charge. (4) Protons are pulled out of the nuclei of atoms in the tape and move onto your finger.

This question focuses on reasoning about equilibrium inside the nickel block shown in Figure 14.92. Start with these premises:

  • The definition of equilibrium inside a conductor and
  • The relationship between average drift speed and electric field

in a conductor to reason about which situations are possibleinside the nickel block at equilibrium. Some of the situations listed below are possible, some are ruled out by one premise, and some are ruled out by two premises. If a situation is ruled out by two premises, choose both.

Case 1:\({\bf{\bar v = 0}}\)and \({{\bf{E}}_{{\bf{net}}}}{\bf{ = 0}}\) (1) Possible, (2) Not possible by definition of equilibrium, (3) Not possible because \({\bf{\bar v = u}}{{\bf{E}}_{{\bf{net}}}}\)

Case 2:\({\bf{\bar v = 0}}\)and \({{\bf{E}}_{{\bf{net}}}}{\bf{ > 0}}\) (1) Possible, (2) Not possible by definition of equilibrium, (3) Not possible because \({\bf{\bar v = u}}{{\bf{E}}_{{\bf{net}}}}\)

Case 3:\({\bf{\bar v > 0}}\)and \({{\bf{E}}_{{\bf{net}}}}{\bf{ = 0}}\) (1) Possible, (2) Not possible by definition of equilibrium, (3) Not possible because \({\bf{\bar v = u}}{{\bf{E}}_{{\bf{net}}}}\)

Case 4:\({\bf{\bar v > 0}}\)and \({{\bf{E}}_{{\bf{net}}}}{\bf{ > 0}}\) (1) Possible, (2) Not possible by definition of equilibrium, (3) Not possible because \({\bf{\bar v = u}}{{\bf{E}}_{{\bf{net}}}}\)

Now that you have considered each case, in equilibrium, which one is the only situation that is physically possible? (1) Case 1, (2) Case 2, (3) Case 3, (4) Case 4

Can you charge a piece of plastic by induction? Explain, using diagram. Compare with the amount of charging obtained when you charge a piece of metal by induction.

A student said, “When you touch a charged piece of metal, the metal is no longer charged: all the charge on the metal is neutralized.” As a practical matter, this is nearly correct, but it Isn’t exactly right. What’s wrong with saying that all the charge on the metal is neutralized?

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