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(a) Which of the diagrams () in Figure correctly displays the polarization of a metal sphere by an electric field that points to the left, using the conventions discussed in this chapter? (b) Which of the diagrams () in Figurecorrectly displays the polarization of a plastic sphere by an electric field that points to the left, using the conventions discussed in this chapter?

Short Answer

Expert verified

(a) Diagram A correctly displays the polarization of a metal sphere

(b) Diagram B correctly displays the polarization of a plastic sphere

Step by step solution

01

Significance of the electric field and Polarization

The electric field is referred to as a region that is beneficial for a charged particle to exert force on another electrically charged particle.

Polarization is described as a property of electromagnetic radiation which is beneficial for relating the magnitude and the direction of the electric field in a specific manner.

02

Step 2:-(a) Determination of the polarization of a metal sphere

Diagram B shows that the dipoles are distributed inside the sphere which is not true. Also, this option is incorrect as due to polarization, the positive and the negative charges should be at the surface.

Diagram C shows that the positive and the negative charges are uniformly distributed over the surface and the dipoles are inside the sphere. This diagram is incorrect as due to polarization; no dipole should be inside the sphere.

Diagram D shows that negative and positive charges are uniformly distributed over the surface of the spheres. This option is incorrect as the electric field points to the left, then the negative charges should be left of that sphere.

Diagram E shows that the dipoles are distributed inside the sphere which is not true. This option is incorrect as due to polarization, the positive and the negative charges should be at the surface.

The diagram F shows that the positive and the negative charges are uniformly distributed over the surface and the dipoles are inside the sphere after one another. This diagram is incorrect as due to polarization; no dipole should be inside the sphere.

Diagram A shows that the positive and the negative charges are uniformly distributed over the surface of the sphere. This option is correct as ofthe sea of the electrons mainly shifts in the opposite direction of the electric field and the electric field points to the left of the sphere, so the negative charges will be at the left and the positive charges will be at the right of the sphere.

Thus, diagram A correctly displays the polarization of a metal sphere.

03

Step 3:-(b) Determination of the polarization of a plastic sphere

Diagram A shows that the positive and the negative charges are uniformly distributed over the surface of the sphere. This option is incorrect as due to the polarization of the plastic sphere; dipoles are being induced by the electric field inside the neutral atoms in the plastic.

Diagram C shows that the positive and the negative charges are uniformly distributed over the surface and the dipoles are inside the sphere. This option is incorrect as due to the polarization of the plastic spheres; no charges should be at the surface of the plastic sphere.

Diagram D shows that negative and positive charges are uniformly distributed over the surface of the spheres. This option is incorrect as due to the polarization of the plastic sphere; dipoles are being induced by the electric field inside the neutral atoms in the plastic.

Diagram E shows that the dipoles are distributed inside the sphere. This option is incorrect because the electrons should be at the left of the sphere after the positive charges inside the dipole as the electric field points towards the left.

Diagram F shows that the positive and the negative charges are uniformly distributed over the surface and the dipoles are inside the sphere after one another. This option is incorrect as due to the polarization of the plastic spheres; no charges should be at the surface of the plastic sphere.

Diagram B shows that the dipoles are distributed inside the sphere. This option is correct asdue to the polarization of the plastic sphere; dipoles are being induced by the electric field inside the neutral atoms in the plastic. As the electric field points to the left, then the electrons should point towards the left inside the sphere and in this diagram, the electrons are pointing to the left.

Thus, diagram B correctly displays the polarization of a plastic sphere.

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Most popular questions from this chapter

Is the following statement true or false? If true, what principle makes it true? If false, give a counterexample or say why. See Figure 14.67.

โ€œThe electric field Epointat the center of an induced dipole, due to the point charge, is equal in magnitude and opposite in direction to the electric field Edipoleat the location of the point charge, due to the induced dipole.โ€

A carbon atom is composed of 6 protons, 6 neutrons, and 6 electrons. What is the net charge of this atom? A neutral chlorine atom contains 17 protons and 17 electrons. When a chlorine atom gains one extra electron, it becomes a chloride ion. What is the net charge of a chloride ion?

: A thin, hollow spherical plastic shell of radius \({\bf{R}}\)carries a uniformly distributed negative charge \({\bf{ - Q}}\). A slice through the plastic shell is shown in Figure 14.95. To the left of the spherical shell are four charges packed closely together as shown (the distance \({\bf{s}}\) is shown greatly enlarged for clarity). The distance from the center of the four charges to the center of the plastic shell is \({\bf{L}}\) , which is much larger than \({\bf{s}}\left( {{\bf{L}} \gg {\bf{s}}} \right)\). Remember that a uniformly charged sphere makes an electric field as though all the charge were concentrated at the center of the sphere.

(a)Calculate the \({\bf{x}}\) and \({\bf{y}}\) components of the electric field at location B, a distance \({\bf{b}}\) to the right of the outer surface of the plastic shell. Explain briefly, including showing the electric field on a diagram. Your results should not contain any symbols other than the given quantities \({\bf{R,Q,q,s,L}}\), and \({\bf{b}}\)(and fundamental constants). You need not simplify the final algebraic results except for taking into account the fact that \({\bf{L}} \gg {\bf{s}}\).

(b)What simplifying assumption did you have to make in part (a)?

(c)The plastic shell is removed and replaced by an uncharged metal ball, as in Figure 14.96. At location Ainside the metal ball, a distance \({\bf{b}}\)to the left of the outer surface of the ball, accurately draw and label the electric field\({{\bf{\vec E}}_{{\bf{ball}}}}\) due to the ball charges and the electric field \({{\bf{\vec E}}_{\bf{4}}}\) of the four charges. Explain briefly.

(d)Show the distribution of ball charges.

(e)Calculate the \({\bf{x}}\) and \({\bf{y}}\) components of the net electric field at location A.

Explain briefly why the attraction between a point charge and a dipole has a different distance dependence for induced dipoles (1/r5 ) than for permanent dipoles (1/r3 ). (You need not explain either situation in full detail: just explain why there is this difference in their behavior.)

A student asked, "Since the positive nucleus of the atom is hidden inside a negative electron cloud, why doesn't all matter appear to be negatively charged?" Explain to the student the flaw in this reasoning.

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