Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

You have two identical neutral metal spheres labeled A and B, mounted on insulating posts, and you have a plastic pen that charges negatively when you rub it on your hair (Figure 14.77).


(a) (+ and −) Explain in detail, including diagrams, what operations you would carry out to give sphere A some positive charge and sphere B an equal amount of negative charge. (b) (+ and +) Explain in detail, including diagrams, what operations you would carry out on the neutral spheres to give sphere A some positive charge and sphere B an equal amount of positive charge (the spheres are initially uncharged).

Short Answer

Expert verified

(a) When the pen is brought near to A then it will get positively charged and B will get negatively charged due to induction.

(b) When a negatively charged pen is brought near the neutral spheres then, they will get positively charged.

Step by step solution

01

the Significance of the induction charging for spheres

Charging by induction states that an uncharged particle can get charged if it is kept beside a charged particle.

Also, induction charging is a process in which charging an object without touching the object is grounded on a “neutrally charged material”.

The induction charging gives the operations needed to charge both the spheres A and B.

02

Determination of the operations needed for giving sphere A, a positive charge and sphere B, a negative charge

(a)

The diagram for explaining the operations is shown below-

Initially, both the bodies are neutral, after rubbing, one sphere gets one type of charge and another sphere gets an opposite charge of the same amount. However, this is possible due to the fact of charging by induction. So, when a negatively charged pen is brought near sphere A, then it gets positively charged, and when the pen is brought near sphere B, then it gets negatively charged due to the fact of induction.

Thus, when the pen is brought near to A then it will get positively charged and B will get negatively charged due to induction.

03

Determination of the operations needed for giving positive charge to both the spheres

(b)

The diagram for explaining the operations is shown below,

In this case, the spheres will be kept at some distance to avoid induction and the pen will bring near both of them to make them positively chargedwith an equal amount of charge due to the fact of induction.

Thus, when a negatively charged pen is brought near the neutral spheres then, they will get positively charged with an equal amount of charge.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following are true? Select all that apply. (1) In equilibrium, there is no net flow of mobile charged particles inside a conductor. (2) The electric field from an external charge cannot penetrate to the center of a block of iron. (3) The net electric field inside a block of aluminum is zero under all circumstances. (4) If the net electric field at a particular location inside a piece of metal is not zero, the metal is not in equilibrium. (5) The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium.

Blocks A and B are identical metal blocks. Initially block A is neutral, and block B has a net charge of5nC.Using insulating handles, the blocks are moved so they touch each other. After touching for a few seconds, the blocks are separated (again using insulating handles). (a) What is the final charge of block A? (b) What happened while the blocks were in contact with each other? (1) Protons moved from block B to block A. (2) Positrons moved from block B to block A. (3) Electrons moved from block A to block B. (4) Both protons and electrons moved. (5) No charged particles moved.

An electric field is applied to a solution containing bromide ions. As a result, the ions move through the solution with an average drift speed of 3.7×10-7m/s. The mobility of bromide ions in solution is 8.1×10-8(m/s)(N/C). What is the magnitude of the net electric field inside the solution?

You have three metal blocks marked A, B, and C, sitting on insulating stands. Block A is charged, but blocks B and C are neutral (Figure 14.76).

Without using any additional equipment and without altering the amount of charge on block A, explain how you could make block B be chargedand block C be charged. Explain your procedure in detail, including diagrams of the charge distributions at each step in the process.

A positive charge is located between a neutral block of plastic and a neutral block of copper (Figure 14.68). Draw the approximate charge distribution for this situation.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free