Question

If the particle in Figure 13.62 is a proton, and the electric field ${\overrightarrow{\mathbf{E}}}_{\mathbf{1}}$has the value localid="1656913137210" $\mathbf{(}\mathbf{2}\mathbf{\times }{\mathbf{10}}^{\mathbf{4}}\mathbf{,}\mathbf{2}\mathbf{\times }{\mathbf{10}}^{\mathbf{4}}\mathbf{,}\mathbf{0}\mathbf{)}\mathbf{N}\mathbf{/}\mathbf{C}$, what is the force ${\overrightarrow{\mathbf{F}}}_{\mathbf{2}}$on the proton?

Short answer

The force exerted on proton is$\left(3.2\times {10}^{-15},3.2\times {10}^{-15},0\right)\mathrm{N}$ .

Step-by-step solution

Identification of given data

The given data can be listed below,

• The value of electric field is,$\overrightarrow{E}=\left(2\times {10}^4,2\times {10}^4,0\right)\mathrm{N}/\mathrm{C}$ .

Concept/Significance of coulomb force

The electrostatic force is a force that attracts and repels particles due to their electric charges. The electrostatic force is the electric force between two stationary charged substances. Coulomb's Force is another name for it.

Determination of the force F→2 on the proton

The force on proton is given by,

$\overrightarrow{F}=\overrightarrow{E}q$

Here, $\overrightarrow{E}$ is the electric field due to proton and q is the charge on the proton whose value is$1.6\times {10}^{-19}C$ .

Substitute all the values in the above,

$$\begin{gathered} \overrightarrow{F}=\left(2\times {10}^4,2\times {10}^4,0\right)\mathrm{N}/\mathrm{C}\left(1.6\times {10}^{-19}\mathrm{C}\right) \\ =\left(3.2\times {10}^{-15},3.2\times {10}^{-15},0\right)\mathrm{N} \end{gathered}$$

Thus, the force exerted on proton is$\left(3.2\times {10}^{-15},3.2\times {10}^{-15},0\right)\mathrm{N}$ .