Question

An electron in a region in which there is an electric field experiences a force of magnitude$\mathbf{3}\mathbf{.}\mathbf{8}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{16}}\mathbf{}\mathbf{N}$ . What is the magnitude of the electric field at the location of the electron?

Short answer

The magnitude of the electric field electron is $2.37\times {10}^3\mathrm{N}/\mathrm{C}$.

Step-by-step solution

Identification of given data

The given data can be listed below,

The magnitude of the force is$F=3.8\times {10}^{-16}\mathrm{N}$

Concept/Significance of electric field.

The forces acting on charges in an electric field are calculated in an abstract method. While a field is undeniably real, it lacks the characteristics of a particle or a mass.

Determination of the magnitude of the electric field at the location of the electron

The electric field of an electron is given by,

$E=\frac{F}{q}$

Here, F is the force acting on the electron and q is the charge on the electron.

Substitute values in the above,

$$\begin{gathered} E=\frac{3.8\times {10}^{-16}N}{1.6\times {10}^{-19}C} \\ =2.37\times {10}^3\mathrm{N}/\mathrm{C} \end{gathered}$$

Thus, the magnitude of the electric field electron is $2.37\times {10}^3\mathrm{N}/\mathrm{C}$.