Chapter 15: Q4Q (page 616)
A rod with uniformly distributed charge
Short Answer
The approximate equation can be used.
Chapter 15: Q4Q (page 616)
A rod with uniformly distributed charge
The approximate equation can be used.
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Get started for freeTwo rings of radius 2 cm are 20 cm apart and concentric with a common horizontal x axis. What is the magnitude of the electric field midway between the rings if both rings carry a charge of +35 nC?
Question: Breakdown field strength for air is roughly . If the electric field is greater than this value, the air becomes a conductor. (a) There is a limit to the amount of charge that you can put on a metal sphere in air. If you slightly exceed this limit, why would breakdown occur, and why would the breakdown occur very near the surface of the sphere, rather than somewhere else? (b) How much excess charge can you put on a metal sphere of radius without causing breakdown in the neighboring air, which would discharge the sphere? (c) How much excess charge can you put on a metal sphere of onlyradius? These results hint at the reason why a highly charged piece of metal tends to spark at places where the radius of curvature is small, or at places where there are sharp points.
A solid metal ball of radius 1.5 cm bearing a charge of −17 nC is located near a solid plastic ball of radius 2 cm bearing a uniformly distributed charge of +7 nC (Figure 15.62) on its outer surface. The distance between the centers of the balls is 9 cm. (a) Show the approximate charge distribution in and on each ball. (b) What is the electric field at the center of the metal ball due only to the charges on the plastic ball? (c) What is the net electric field at the center of the metal ball? (d) What is the electric field at the center of the metal ball due only to the charges on the surface of the metal ball?
For a disk of radius R=20cm and
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How good are the approximate equations at this distance? For the same disk, calculate E at a distance of 5 cm (50 mm) using all three equations. How good are the approximate equations at this distance?
A large, thin plastic disk with radiusR = 1.5 m carries a uniformly distributed charge of −Q = −3 × 10−5 C as shown in Figure 15.59. A circular piece of aluminum foil is placed d = 3 mm from the disk, parallel to the disk. The foil has a radius of r = 2 cm and a thickness t = 1 mm.
(a) Show the charge distribution on the close-up of the foil. (b) Calculate the magnitude and direction of the electric field at location × at the center of the foil, inside the foil. (c) Calculate the magnitude q of the charge on the left circular face of the foil.
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