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What would be the potential difference VC-VBacross the thin resistor in Figure 18.103 if the battery emf is3.5V ? Assume that the electric field in the thick wires is very small (so that the potential differences along the thick wires are negligible). Do you have enough information to determine the current in the circuit?

Short Answer

Expert verified

The potential difference VC-VBis 3.5Vand the information is not enough to calculate the current in the circuit.

Step by step solution

01

Write the given data from the question.

The emf of the battery,VA-VD=3.5V

The electric field thick wire us very small due to this the potential difference across it is negligible.

The voltage difference,VB-VA0V

The voltage difference,VD-VC=0V

02

Determine the formulas to calculate the potential difference and current in the circuit.

The average drift speed of the mobile electron is given by the product of the electron mobility and electric field.

V=UE …… (i)

Here, U is the electron mobility and E is the electric field.

The expression to calculate the current in the circuit is given as follows.

i=nAv …… (ii)

Here, A is the area of the wire.

03

Calculate the potential difference and current in the circuit.

According to the Kirchhoff’s Voltage law, the algebraic sum of the voltage in the circuit is always equal to zero.

V=0(VB-VA)+(VC-VB)+(VD-VC)+(VA-VD)=00+(VC-VB)+0+3.5=0(VC-VB)=-3.5V

The electrical field in the circuit is given by,

E=VL

Derive the expression for the current in the circuit.

SubstituteuE for V into equation (ii).

i=nAuE

SubstituteV/L forE into above equation.

i=nAuVL

From the above equation, it is clear that, to calculate the current in the circuit we need property of the resistor. Therefore, the required information to calculate the current in the circuit is not enough.

Hence, the potential difference VC-VBis 3.5Vand the information is not enough to calculate the current in the circuit.

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