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Chapter 18: Q13Q (page 755)

Compare the direction of the average electric field inside a battery to the direction of the electric field in the wires and resistors of a circuit.

Short Answer

Expert verified

The average electric field inside a battery and the field in the wires and resistors of the circuit are both directed from the positive terminal to the negative terminal of the battery.

Step by step solution

01

Given data

Electric field is present both inside a battery and outside in the circuit.

02

Direction of electric field

A electric field flows outwards in case of the positive charge and inwards in case of the negative charge.

03

Comparison of the electric fields outside and inside the battery

A battery has a positive terminal and negative terminal. Both inside the battery and outside, the electric field is directed from the positive terminal to the negative terminal. The electric field outside in the circuit causes the flow of charges. The electric field inside the battery doesn't cause the flow of charges.

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Most popular questions from this chapter

A Nichrome wire 48 cm long and 0.25 mm in diameter is connected to a 1.6 V flashlight battery. What is the electric field inside the wire? Why you don’t have to know how the wire is bent? How would your answer change if the wire diameter change were 0.20 mm? (Not that the electric field in the wire is quiet small compared to the electric field near a charged tape.)

Describe the following attributes of a metal wire in steady

state vs. equilibrium:

Metal Wire

Steady-state

Equilibrium

Location of excess charge

Motion of mobile electrons

inside the metal wire

Inside a chemical battery it is not actually individual electrons that are transported from the + end to the – end. At the + end of the battery an “acceptor” molecule picks up an electron entering the battery, and at the – end a different “donor” molecule gives up an electron, which leaves the battery. Ions rather than electrons move between the two ends to support the charge inside the battery.

When the supplies of acceptor and donor molecules are used up in a chemical battery, the battery is dead because it can no longer accept or electron. The electron current in electron per second times the number of seconds of battery life, is equal to the number of donor molecules in the battery.

A flashlight battery contains approximately half a mole of donor molecules. The electron current through a thick filament bulb powered by two flashlight batteries in series is about 0.3 A. About how many hours will the batteries keep this bulb lit?

A Nichrome wire 30 cm long and 0.25 mm in diameter is connected to a 1.5 V flashlight battery. What is the electric field inside the wire? Why you don’t have to know how the wire is bent? How would your answer change if the wire diameter change were 0.35 mm? (Not that the electric field in the wire is quiet small compared to the electric field near a charged tape.)

Suppose that a wire leads into another, thinner wire of the same material that has only half the cross-sectional area. In the steady state, the number of electrons per second flowing through the thick wire must be equal to the number of electrons per second flowing through the thin wire. If the electric field \({E_1}\) in the thick wire is \(1 \times 1{0^{ - 2}}\;N/C\), what is the electric field \({E_2}\) in the thinner wire?
See all solutions

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