Question

Question:A certain metal with atomic mass 2 × 10−25 kg has an interatomic bond with length 2.1 × 10−10 m and stiffness 40 N/m. What is the speed of sound in a rod made of this metal?

Short answer

V=3500m/s

Step-by-step solution

Given Information

Atomic mass =2×10^-25kg

Length= 2.1×10^-10m

Stiffness=40N/m

Formula speed of sound in a rod

$V=d\sqrt{\frac{Ks}{m}}$

Where,

d=length

k_{s= stiffness}

m=mass

calculation of speed of sound in a rod

$V=d\sqrt{\frac{Ks}{m}}$

$$\begin{gathered} V=2.1\times {10}^{-10}\sqrt{\frac{40}{2.0\times {10}^{-25}}} \\ V=2969.848\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right. \end{gathered}$$