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Question: How does the final (equilibrium) charge on the capacitor plates depend on the particular resistor (for example, the kind of bulb or the length of Nichrome wire) in the circuit during charging? Explain briefly.

Short Answer

Expert verified

The capacitor's charging depends on the cross-sectional area of the wire or filament of the bulb.

Step by step solution

01

Assume some data on behalf of given question.

Let assume the resistance of the filament of the nichrome wire isR .

Area of the capacitor plates is A.

02

Determine the formulas that shows the relation between the final charge and resistance of the element.

The electron charge or current is defined as the number of the electron enter the wire every second.

The expression to calculate the electron current at the location Dis given as follows.

role="math" localid="1668592073069" i=nAμE …… (i)

Here, is the number of the electron, is the cross-sectional area, is the mobility and is the electrical field.

03

Determine that how the final charge on the capacitor depends on the particular resistance.

The electric field inside the capacitor plates is constant, and the current in the filament of the bulb and wire varies during the charging. The mobility is a constant value for the particular material. Therefore, the current depends on the cross-sectional area.

From equation (i), the current in the bulb's filament is directly proportional to the cross-sectional area. If the cross-sectional area of the wire or filament of the bulb is low, then the current through the wire and bulb's filament is low.

Hence, the capacitor's charging depends on the cross-sectional area of the wire or filament of the bulb.

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Most popular questions from this chapter

A long Iron slab of width w and height h emerges from a furnace, as shown in Figure 19.79. Because the end of the slab near the furnace is hot and the other end Is cold, the electron mobility increases significantly with the distance x. The electron mobility is u=u0+kxwhere u0is the mobility of the iron at the hot end of the slab. There are n iron atoms per cubic meter, and each atom contributes one electron to the sea of the mobile electron (we can neglect the small thermal expansion of the iron). A steady state conventional current runs through the slab from the hot end towards cold end, and an ammeter (not shown) measures the current to have a magnitude I in amperes. A voltmeter is connected to two locations a distance d apart, as shown. (a) Show the electric field inside the slab at two locations marked with ×. Pay attention to the relative magnitudes of the two vectors that you draw. (b) Explain why the magnitude of the electric field is different at these two locations. (c) At a distance x from the left voltmeter connection, what is the magnitude of the electric field in terms x and the given quantities w,h,d,u0,k,l, and n ( and fundamental constants)? (d) What is the sign of potential difference displayed on the voltmeter? Explain briefly. (e) In terms of the given quantitiesw,h,d,u0,k,l, and n and ( and fundamental constants), what is the magnitude of the voltmeter reading? Check your work. (f) What is the resistance of this length of the iron slab?

A circuit consists of two batteries (with negligible resistance), six ohmic resistors and connecting wires that have negligible resistance. The resistance R1is 10Ω, R2 is 20Ω, R3 is 30Ω, R4is 12Ω, R5is 15Ω and R6 is 20Ω. Unknown currents I1,I2 ,I3 ,I4 , I5 and I6 have their directions marked on the circuit diagram in figure 19.87.

(a) Write down a set of equations that could be solved for the six unknown currents. Make sure you can explain how to you got these equations. (b) When a correct set of equations is solved the currents are as follows (to the nearest miiampeares) I1=0.4394A, I2=0.3312A, I3=0.0065A, I4=0.1082A, I5=0.3247Aand I6=0.4329A. Check your equations by substituting in these numbers. (c) Suppose that you connect the negative lead of a voltmeter to location C. What does the voltmeter read, including both magnitude and sign? (d) What does the power output of the 5 V battery? (e) Resistor is made of a very thin metal wire that is 3 mm long, with a diameter of 0.1 mm. What is the electric field inside the metal resistor.

A capacitor with a slab of glass between the plates is connected to a battery by Nichrome wires and allowed to charge completely. Then the slab of glass is removed. Describe and explain what happens. Include diagrams. If you give a direction for a current, state whether you are describing electron current or conventional current.

A certain 6 V battery delivers 12 A when short circuited. How much current does battery deliver when 1Ω resistor is connected to it?

The conductivity of tungsten at room temperature,1.8×107A/m2/V/m , is significantly smaller than that of copper. At the very high temperature of a glowing light-bulb filament (nearly 3000 kelvins), the conductivity of tungsten is 18 times smaller than it is at room temperature. The tungsten filament of a thick-filament bulb has a radius of about 0.015 mm. Calculate the electric field required to drive 0.20 A of current through the glowing bulb and show that it is very large compared to the field in the connecting copper wires.

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