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When a single thin-filament bulb is connected to a 1.5Vbattery, the current through the battery is about80mAIf you add another thin-filament bulb in parallel, the battery current of course increase to160mA. Is the battery ohmic? That is, is the current through the battery proportional to the potential difference across the battery?

Short Answer

Expert verified

No

Step by step solution

01

Given Data

VoltageV=1.5VCurrentI1=80mAI2=160mA

02

Concept

Generally, the current is proportional to the difference of electric potential. The current is inversely proportional to the resistance.

03

Find the battery is ohmic

  • The battery is not ohmic.
  • The current is not proportional to voltage.
  • If you double the current through a battery, the battery voltage hardly changes at all.
  • The battery voltage certainly does not double and will actually decrease slightly.
  • The battery voltage is not proportional to the current.

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Most popular questions from this chapter

A circuit consists of a battery, whose emf is K, and five Nichrome wires, three thick and two thin as shown in Figure 19.78. The thicknesses of the wires have been exaggerated in order to give you room to draw inside the wires. The internal resistance of the battery is negligible compared to the resistance of the wires. The voltmeter is not attached until part (e) of the problem. (a) Draw and label appropriately the electric field at the locations marked ร— inside the wires, paying attention to appropriate relative magnitudes of the vectors that you draw. (b) Show the approximate distribution of charges for this circuit. Make the important aspects of the charge distribution very clear in your drawing, supplementing your diagram if necessary with very brief written descriptions on the diagram. Make sure that parts (a) and (b) of this problem are consistent with each other. (c) Assume that you know the mobile-electron density n and the electron mobility u at room temperature for Nichrome. The lengths (L1,L2,L3)and diameters (d1,d2)of the wires are given on the diagram. Calculate accurately the number of electrons that leave the negative end of the battery every second. Assume that no part of the circuit gets very hot. Express your result in terms of the given quantities (K,L1,L2,L3,d1,d2,nandu). Explain your work and identify the principles you are using. (d) In the case that d2โ‰ชd1, what is the approximate number of electrons that leave the negative end of every second? (e) A voltmeter is attached to the circuit with its + lead connected to location B (halfway along the leftmost thick wire) and its - lead connected to location C (halfway along the leftmost thin wire). In the case that d2โ‰ชd1, what is the approximate voltage shown on the voltmeter, including sign? Express your result in terms of the given quantities(K,L1,L2,L3,d1,d2,nandu).

A circuit consists of two batteries (with negligible internal resistance), five ohmic resistors (Figure 19.88). The connecting wires that have negligible resistance. The letters A through are shown to make it possible to refer to specific parts of the circuit.

(a) Write all the equations necessary to solve for the unknown currents I1, I2, I3, I4 and I5, whose directions are indicated on the circuit diagram. Do not solve the equations but do explain very clearly what your equations are based on and to what they refer.

Assume that a computer program has solved your equations in terms of known battery voltages and known resistances so that the currents I1, I2,I3 ,I4and I5are are known. (b) In terms of known quantities calculate VD-VAand check that your sign makes sense. (c) In terms of known quantities, calculate the power produced in battery number 2.

You are marooned on a desert island full of all kinds of standard electrical apparatus including a sensitive voltmeter, but you donโ€™t have an ammeter. Explain how you could use the voltmeter to measure currents.

The capacitor in Figure 19.68 is initially uncharged, then the circuit is connected. Which graph in Figure 19.66 best describes the magnitude of the net electric field at location A (inside the connecting wire) as a function of time?

The two circuits shown in Figure 19.59 have different capacitors but the same batteries and thin-filament bulbs. The capacitors in circuit 1and circuit 2areidentical exceptthat the capacitor in circuit 2was constructed with its plates closer together. Both capacitors have air between their plates. The capacitors are initially uncharged. In each circuit the batteries are connected for a short time compared to the time required to reach equilibrium, and then they are disconnected. In which circuit (1or 2) does the capacitor now have more charge? Explain your reasoning in detail.

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