Chapter 9: Problem 12
Solve $$ \sin 2 \theta=-0.4010 \quad 0 \leq \theta \leq 2 \pi $$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 9: Problem 12
Solve $$ \sin 2 \theta=-0.4010 \quad 0 \leq \theta \leq 2 \pi $$
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeSolve (a) \(\sin \theta=0.3510,0^{\circ} \leq \theta \leq 360^{\circ}\) (b) \(\sin \theta=0.4161,0 \leq \theta \leq 2 \pi\) (c) \(\cos t=-0.3778,0 \leq t \leq 2 \pi\) (d) \(\cos x=0.7654,0^{\circ} \leq x \leq 360^{\circ}\) (e) \(\tan y=1.7136,0^{\circ} \leq y \leq 360^{\circ}\) (f) \(\tan y=-0.3006,0^{\circ} \leq y \leq 360^{\circ}\)
Solve $$ \tan \left(\frac{2 x}{3}\right)=0.7 \quad 0 \leq x \leq 2 \pi $$
A current, \(i(t)\), varies with time, \(t\), and is given by $$ i(t)=30 \cos (t-0.4) \quad t \geq 0 $$ (a) Find the time when the current is first zero. (b) Find the time when the current reaches its first peak.
An arc of a circle, radius \(5 \mathrm{~cm}\), subtends an angle of \(\frac{3 \pi}{4}\) radians at the centre. Calculate the length of the arc.
Show \(\tan \left(360^{\circ}-\theta\right)=-\tan \theta\)
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