Chapter 7: Problem 4
Solve the simultaneous equations $$ 3 x-2 y=11,5 x+7 y=39 $$
Short Answer
Expert verified
Answer: The values for \(x\) and \(y\) that satisfy the given simultaneous equations are \(x = 5\) and \(y = 2\).
Step by step solution
01
Write down the equations
Write down the simultaneous equations:
$$
3x - 2y = 11 \hspace{1cm} (1)
$$
$$
5x + 7y = 39 \hspace{1cm} (2)
$$
02
Solve one equation for one variable
We will solve equation (1) for \(x\):
$$
x = \frac{11 + 2y}{3}
$$
03
Substitute the result into the other equation
Now substitute the result from Step 2 into equation (2):
$$
5\left(\frac{11 + 2y}{3}\right) + 7y = 39
$$
04
Solve the resulting equation for the remaining variable
Simplify the equation and solve for \(y\):
$$
\frac{55 + 10y}{3} + 7y = 39
$$
Multiply both sides by 3 to eliminate the fraction:
$$
55 + 10y + 21y = 117
$$
Combine like terms:
$$
31y = 62
$$
Now, solve for \(y\):
$$
y = \frac{62}{31}
$$
$$
y = 2
$$
05
Substitute the found value back into the equation from Step 2
Substitute the value of \(y\) we found in Step 4 into the equation for \(x\), found in Step 2:
$$
x = \frac{11 + 2(2)}{3}
$$
$$
x = \frac{15}{3}
$$
$$
x = 5
$$
06
Check the solution in both given equations
Check the values \(x = 5\) and \(y = 2\) in both equation (1) and equation (2).
For equation (1), \(3x - 2y = 11\):
$$
3(5) - 2(2) = 11
$$
$$
15 - 4 = 11
$$
$$
11 = 11
$$
For equation (2), \(5x + 7y = 39\):
$$
5(5) + 7(2) = 39
$$
$$
25 + 14 = 39
$$
$$
39 = 39
$$
Both equations are true, so the solution is \(x = 5\) and \(y = 2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Equations
Linear equations are mathematical expressions where each term is either a constant or the product of a constant and a single variable. In simpler terms, they form a straight line when graphed on a coordinate plane. This means they have no exponent higher than one or anything multiplying variables together.
Linear equations generally come in the form \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants, and \(x\), \(y\) are variables. In our given problem, we have two linear equations:
Linear equations generally come in the form \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants, and \(x\), \(y\) are variables. In our given problem, we have two linear equations:
- \(3x - 2y = 11\)
- \(5x + 7y = 39\)
Substitution Method
The substitution method is a technique for solving simultaneous equations. The idea is to solve one equation for one variable and then substitute this expression into the other equation. This reduces the number of variables, simplifying the problem.
In our problem, we first solve the first equation for \(x\):
In our problem, we first solve the first equation for \(x\):
- Equation (1): \(3x - 2y = 11\)
- Rearranging for \(x\): \(x = \frac{11 + 2y}{3}\)
- Equation (2) becomes \(5\left(\frac{11 + 2y}{3}\right) + 7y = 39\)
Solving Equations
Once you've substituted one equation into another, you're left with a single equation that usually requires simplification. Solving equations involves isolating the variable, using basic arithmetic to achieve the goal.
After substituting, our equation is:
After substituting, our equation is:
- \(\frac{55 + 10y}{3} + 7y = 39\)
- Multiply through by 3 to clear the fraction: \(55 + 10y + 21y = 117\)
- Combine like terms: \(31y = 62\)
- Finally, solve for \(y\): \(y = 2\)
- \(x = \frac{11 + 2(2)}{3}\)
- Simplify to find \(x = 5\)