Chapter 5: Problem 31
Express as a single fraction $$ \frac{a_{1}}{s+p_{1}}+\frac{a_{2}}{s+p_{2}} $$
Short Answer
Expert verified
Question: Express the sum of the given fractions as a single fraction: $$\frac{a_{1}}{s+p_{1}} + \frac{a_{2}}{s+p_{2}}$$
Answer: The sum of the given fractions expressed as a single fraction is: $$\frac{a_{1}(s+p_{2})+a_{2}(s+p_{1})}{(s+p_{1})(s+p_{2})}$$
Step by step solution
01
Identify the denominators
Identify the denominators of the given fractions. In this case, they are \((s + p_1)\) and \((s + p_2)\).
02
Find a common denominator
To find a common denominator, we can multiply the two denominators together, as this will always be a multiple of both denominators. So, in this case, the common denominator will be \((s+p_1)(s+p_2)\).
03
Convert fractions to their equivalents
Now that we have a common denominator, we can convert the fractions into their equivalents with the same denominator. We do this by multiplying the numerator and denominator of each fraction by the necessary factor:
$$
\frac{a_{1}}{s+p_{1}}\times\frac{s+p_{2}}{s+p_{2}} = \frac{a_{1}(s+p_{2})}{(s+p_{1})(s+p_{2})} \\
\frac{a_{2}}{s+p_{2}}\times\frac{s+p_{1}}{s+p_{1}} = \frac{a_{2}(s+p_{1})}{(s+p_{1})(s+p_{2})}
$$
04
Add the equivalent fractions
Now that the fractions have the same denominator, we can add them together by adding their numerators:
$$
\frac{a_{1}(s+p_{2})}{(s+p_{1})(s+p_{2})} + \frac{a_{2}(s+p_{1})}{(s+p_{1})(s+p_{2})} = \frac{a_{1}(s+p_{2})+a_{2}(s+p_{1})}{(s+p_{1})(s+p_{2})}
$$
05
Final answer
The sum of the given fractions expressed as a single fraction is:
$$
\frac{a_{1}(s+p_{2})+a_{2}(s+p_{1})}{(s+p_{1})(s+p_{2})}
$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fractions
Fractions are an essential concept in algebra and mathematics in general. They represent parts of a whole. In other words, a fraction is a way to divide any quantity into equal-sized pieces.
In algebra, you often see fractions with variables in the numerator or denominator, which prepare you for more complex equations, like rational expressions.
Fractions consist of two main parts:
- A numerator (the top number), which indicates how many parts are considered.
- A denominator (the bottom number), which shows the number of equal parts the whole is divided into.
Common Denominator
A common denominator is crucial when you need to add or subtract fractions. It is essentially a common multiple of the denominators involved in your fractions. Having a shared denominator allows for straightforward addition or subtraction.To find a common denominator for \(rac{a_{1}}{s+p_{1}}\) and \(rac{a_{2}}{s+p_{2}}\), one can multiply the two denominator expressions: \((s+p_{1})(s+p_{2})\). This multiplication ensures each individual fraction aligns under a single denominator, setting the stage for their numerators' combination. It's important to note that while multiplying denominators gives a valid common denominator, sometimes you can find simpler ones if you're dealing with numbers instead of algebraic expressions. Nevertheless, multiplying existing denominators is a foolproof method to proceed with algebraic fractions.
Rational Expressions
Rational expressions resemble fractions but involve polynomials both in the numerator and the denominator. These are central in algebra and require mastering similar skills used for simple numerical fractions.
When handling rational expressions:
- Focus on finding equivalent expressions that allow for easy operations like addition or subtraction.
- Simplification often involves factoring polynomials to reduce the complexity of the expression.
- First, find a common denominator.
- Then adjust each fraction's numerator so that it’s equivalent based on this shared denominator.
Simplifying Fractions
Simplifying fractions or rational expressions is the process of reducing them to their simplest form. This involves dividing both the numerator and the denominator by their greatest common factor, or in the case of polynomials, factoring out common terms. Why simplify?
- It makes further calculations more straightforward.
- It presents the expression in its easiest-to-understand format.