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Dynamics - Pressure in a vessel. The pressure in a vessel is \(30 \mathrm{~N} \mathrm{~cm}^{-2}\). If the pressure is reduced by \(\frac{7}{100}\) of its original value, calculate (a) the decrease in pressure, (b) the resulting pressure in the vessel.

Short Answer

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Question: The pressure in a vessel is initially 30 N/cm². If the pressure is reduced by 7%, find (a) the decrease in pressure, and (b) the resulting pressure in the vessel. Answer: (a) The decrease in pressure is 21000 N/m². (b) The resulting pressure in the vessel is 279000 N/m².

Step by step solution

01

Calculate the decrease in pressure

To find the decrease in pressure, we need to calculate \(\frac{7}{100}\) of the original pressure. First, let's convert the given pressure from \(30 N\,cm^{-2}\) to a more widely-used unit, \(N\,m^{-2}\). There are \(100 cm\) in \(1 m\), so the conversion factor is \((100)^{2}\): $$30 \mathrm{\frac{N}{cm^2} \times \frac{(100 cm)^2}{(1 m)^2}} = 300000\,\frac{N}{m^2}.$$ Now, we find the decrease in pressure: $$\mathrm{Decrease\,in\,pressure} = \frac{7}{100} \times 300000\,\frac{N}{m^2} = 21000\,\frac{N}{m^2}.$$
02

Calculate the resulting pressure

To find the resulting pressure in the vessel, subtract the decrease in pressure calculated in Step 1 from the initial pressure: $$\mathrm{Resulting\,pressure} = 300000\,\frac{N}{m^2} - 21000\,\frac{N}{m^2} = 279000\,\frac{N}{m^2}.$$ Therefore, (a) the decrease in pressure is \(21000\,\frac{N}{m^2}\), and (b) the resulting pressure in the vessel is \(279000\,\frac{N}{m^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Understanding unit conversion is essential in pressure calculations. Here, it's necessary to convert the pressure from \(N/cm^2\) to \(N/m^2\), a more commonly used unit. Why do we convert units? This standardizes measurements, making them easier to work with and understand in different contexts. - 1 meter (m) equals 100 centimeters (cm)- To convert from \(N/cm^2\) to \(N/m^2\), use the conversion factor of \(100^2\) because there are \(100 \, cm\) in a \(meter\)- Thus, \(30 \, N/cm^2 \, becomes \, 300000 \, N/m^2\) after conversion. This process helps simplify pressure calculations, providing a standard unit that's widely understood.
Pressure Reduction
Pressure reduction involves calculating how much pressure decreases from its original value. In this problem, the pressure is reduced by \(\frac{7}{100}\) or 7% of its initial value. Here’s how to think about it: - Identify the percentage of reduction, which is \(7\%\) in this case - Multiply this percentage by the initial pressure value to find the decrease For example, if the original pressure is \(300000 \, N/m^2\), a 7% reduction means calculating \(\frac{7}{100} \, of \, 300000\). This equates to a decrease of \(21000 \, N/m^2\). Understanding pressure reduction helps in determining the new or resulting pressure efficiently.
Resulting Pressure
Once you know the decrease in pressure, finding the resulting (or new) pressure is straightforward. You simply subtract the reduced amount from the original pressure: - Original pressure: \(300000 \, N/m^2\)- Decrease in pressure: \(21000 \, N/m^2\) - Resulting pressure: \(300000 \, - \, 21000 = 279000 \, N/m^2\) This subtraction gives the resulting pressure, \(279000 \, N/m^2\), which is the pressure inside the vessel after the change. This step is critical in situations where pressure adjustments are necessary, such as in mechanical systems, fluid dynamics, or various engineering applications.
N/cm² to N/m² Conversion
Converting from \(N/cm^2\) to \(N/m^2\) is a key skill when dealing with pressure measurements. Here's why it's important and how it's done: - \(1 \, m \, = \, 100 \, cm\). Therefore, to convert areas from \(cm^2\) to \(m^2\), multiply by \(100^2\) - \(30 \, N/cm^2 \, \rightarrow \, 30 \, N/cm^2 \, \times \, 10,000 \, cm^2 \, / \, m^2 \, = \, 300,000 \, N/m^2\) Converting these units is not just a formulaic step, but it helps in visualizing and simplifying calculations with standard scientific units, ensuring consistency in problem-solving and data representation.

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