Chapter 11: Problem 1
If \(z=4 \angle \frac{\pi}{6}\) find \(z^{6}\) in polar form.
Short Answer
Expert verified
Answer: The sixth power of the given complex number in polar form is \(z^6 = 4096\angle \pi\).
Step by step solution
01
Identify the given complex number in polar form
The given complex number is \(z=4\angle\frac{\pi}{6}\). Here, \(r=4\) and \(\theta=\frac{\pi}{6}\).
02
Apply De Moivre's theorem
According to De Moivre's theorem, \((r\angle\theta)^n = r^n\angle n\theta\). In this case, we need to find \(z^6\), so we have \(n=6\). Plug in the values of \(r\), \(\theta\), and \(n\) to find the sixth power of \(z\):
\((4\angle\frac{\pi}{6})^6 = 4^6\angle 6\frac{\pi}{6}\)
03
Calculate the result
Using the values we found in the previous step, calculate the result for \(z^6\):
\(4^6\angle 6\frac{\pi}{6} = 4096\angle \pi\)
04
Write the final answer in polar form
So, the sixth power of the given complex number in polar form is:
\(z^6 = 4096\angle \pi\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form
The polar form of a complex number makes it easier to visualize and manage rotations and magnitudes. It expresses a complex number in terms of its distance from the origin, called the modulus, and the angle it forms with the positive real axis, called the argument or phase angle. The polar form of a complex number is written as \( r \angle \theta \), where:
Switching between rectangular (algebraic) form \( z = a + bi \) and polar form requires a bit of trigonometry, where \( r = \sqrt{a^2 + b^2} \) and \( \theta = \tan^{-1}(\frac{b}{a}) \).
- \( r \): This is the modulus or the absolute value of the complex number, which represents the distance of the point from the origin in the complex plane.
- \( \theta \): This is the argument or phase angle, measured in radians, that gives the direction of the point from the origin in the complex plane.
Switching between rectangular (algebraic) form \( z = a + bi \) and polar form requires a bit of trigonometry, where \( r = \sqrt{a^2 + b^2} \) and \( \theta = \tan^{-1}(\frac{b}{a}) \).
Complex Numbers
Complex numbers extend our familiar set of real numbers and encompass solutions to truly exist where real numbers alone fail.Each complex number consists of a real part and an imaginary part, typically expressed as \( z = a + bi \), where:
Understanding complex numbers is crucial for solving quadratic equations and other higher-degree polynomials with real coefficients that lack real roots.
- \( a \): The real part of the complex number.
- \( b \): The imaginary part, which is a real number multiplied by the unit imaginary component \( i \), where \( i^2 = -1 \).
Understanding complex numbers is crucial for solving quadratic equations and other higher-degree polynomials with real coefficients that lack real roots.
Complex Number Multiplication
Multiplying complex numbers can at first seem daunting due to their imaginary component. Yet, multiplying two complex numbers involves more straightforward trigonometric adjustments when they're expressed in polar form. This is where the beauty of the polar form shines.Consider two complex numbers represented in polar form as \( r_1 \angle \theta_1 \) and \( r_2 \angle \theta_2 \). Their product can be found simply by:
This method is not only convenient for straightforward multiplication but also serves as the foundation for De Moivre's Theorem, which raises complex numbers to powers efficiently by adjusting their radius and rotating their angles systematically.
- Multiplying their moduli: Multiply \( r_1 \) and \( r_2 \) to get the system's resulting modulus.
- Adding their angles: Add \( \theta_1 \) and \( \theta_2 \) to find the resultant angle.
This method is not only convenient for straightforward multiplication but also serves as the foundation for De Moivre's Theorem, which raises complex numbers to powers efficiently by adjusting their radius and rotating their angles systematically.