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Verify equation (6.8); that is, findfin spherical coordinates as we did for cylindrical coordinates.

Short Answer

Expert verified

f=erfr+eθ1rfθ+ezfz

Step by step solution

01

Given Information

The given information is the spherical coordinates to be used in solving the question.

02

Definition of Scalar field.

In mathematics and physics, scalar field or scalar-valued function referred to a scalarvalueto everypointin aspace– possiblyphysical space. The scalar may either be a (dimensionless)mathematical numberor aphysical quantity.

03

Find the solution.

Let fr,θ,ϕ be the gradient of a general function in a spherical coordinates.

The gradient is the directional derivative in the form of dfds .

The arc length is equal to which is in the direction of er , which further leads to the derivative dfdr.

In the direction of eθ the arc length isrdθ , which further leads to the derivativedfrθ .

Since the angle ϕ is obtained by rotating around k-axis. The arc length is therefore rsinθdϕ, which gives the directional derivatives in the direction of eθas frsinθϕ .

Therefore, the gradient is f=erfr+eθ1rfθ+ezfz .

Hence, the solution to this problem is f=erfr+eθ1rfθ+ezfz.

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