Question

$\frac{\mathbf{\partial }\mathbf{B}}{\mathbf{\partial }\mathbf{t}}\mathbf{=}\mathbf{-}\mathbf{\nabla }\mathbf{\times }\mathit{E}$

Short answer

$\frac{\partial \mathrm{B}}{\partial \mathrm{t}},\nabla \times E$are both axial vectors.

Step-by-step solution

Given information.

Physics definitions are given.

Definition of one of Maxwell’s equations.

Define one of Maxwell’s equations.

$\frac{\mathbf{\partial }\mathbf{B}}{\mathbf{\partial }\mathbf{t}}\mathbf{=}\mathbf{-}\mathbf{\nabla }\mathbf{\times }\mathit{E}$

Write about the nature of various vectors.

It is proved that B is an axial vector and E is a polar vector.

This implies that $\frac{\partial \mathrm{B}}{\partial \mathrm{t}},\nabla \times E$ are both axial vectors.

This is based on one of Maxwell’s relations.

$\frac{\partial \mathrm{B}}{\partial \mathrm{t}}=-\nabla \times E$