Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Substitute the Pl(x), you found in Problems 4.3 or 5.3into equation (10.6)to find Plm(x) then let x=cosθ to evaluate:

P11(cosθ)

Short Answer

Expert verified

The value of P11(cosθ) is sinθ.

Step by step solution

01

Concept:

An equation similar to Legendre’s equation is-

(1-x2) y"-2xy'+[l(l+1)-m2/1-x2] y=0 (∀ m2≤ l2)

The solution to this equation is of the form

Plm (x)=(1-x2)m/2 dm/dxm (Pl(x))

These solutions are called Associated Legendre Functions.

02

The given information used to evaluate P11 (cosθ):

It is given that

Plm(x) =(1-x2)m/2 dm/dxmPl(x) …… (1)

03

Put l=1 and m=1 in equation (1):

Substitute l=1 and m=1 to obtain,

P11(x) = (1-x2)1/2 d1/dx1 P1(x)

P11(x) = (1-x2)1/2 d/dx P1(x)

P11(x) = (1-x2)1/2 d/dx (x)

P11(x) = (1-x2)1/2 (1)

Therefore,

P11(x) = (1-x2)1/2 …… (2)

04

Substitute x=cos x into equation (2):

On substituting x=cos x into equation (2):

P11(x)=(1-x2)1/2

P11(cos θ)= (1-cos2θ)1/2

P11(cos θ)= (sin2θ)1/2

P11(cos θ)= sinθ

Hence, the required value is P11(cos θ)= sinθ.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free