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A die is thrown 720 times.

(a) Find the probability that3comes up exactly 125 times.

(b) Find the probability that 3 comes up between115and 130 times.

Short Answer

Expert verified

(a) The value required for part a is given below.

fB(120)=0.0345fn(125)=0.035

(b) The value required for part b is given below.

PB(115x130)=0.533Pn(115x130)=0.56

Step by step solution

01

 Step 1: Given Information

A die is thrown 720 times.

02

Definition of the Binomial distribution. 

Frequency distribution of the number of successful outcomes that can be achieved in a given number of trials, each with an equal chance of success.

03

Find the probability that 3  comes up exactly 125  times.

(a)

The formula for binomial distribution states thatf(x)=C(x,n)pxqnx.

n=720p=16q=56x=125

Substitute the values mentioned above in the formula.

fB(120)=C(710,125)(16)120(56)720120fB(120)=0.0345

The formula for corresponding normal approximation states that .f(x)=e(xnp)2/2npq2πnpqf(x)=e(xnp)2/2npq2πnpq

n=720p=16q=56x=125

Substitute the values mentioned above in the formula.

fn(125)=12π×104×0.25fn(125)=0.035

04

Find the probability of between 115  and 130  heads.

(b)

The probability by cumulative function is given below.

PB(115x130)=0.533

Theprobability by normal distribution function is given below.

Pn(115x130)=0.56

The value required for part a is given below.

fB(120)=0.0345fn(125)=0.035

The value required for part b is given below.

PB(115x130)=0.533Pn(115x130)=0.56

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