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Using (3.9), find the general solution of each of the following differential equations. Compare a computer solution and, if necessary, reconcile it with yours. Hint: See comments just after (3.9), and Example .

(1+ex)y+2exy=(1+ex)

Short Answer

Expert verified

Answer:

The general solution of the differential equation is y=ex1+ex+e2x3+C1+ee2.

Step by step solution

01

Given information

The given differential equation is1+exy+2exy=1+exex.

02

Meaning of the first-order differential equation

A first-order differential equation is defined by two variables, x and y, and its function f(x,y)is defined on an XY-plane region.

03

Find the general solution

Write this differential equation to make it in the form y+Py=Q; that is

y+2ex1+exy=ex.

From equation 3.4,

I=โˆซ2ex1+exdx=2In1+exeI=e2In1+ex=1+ex2.

Find a solution for this differential equation.

yeI=โˆซex1+ex2dx=ex+e2x+e3x3+Cy1+ex2=ex1+ex+e2x3+Cy=ex1+ex+e2x3+C1+ex2

Therefore, the general solution of the differential equation is y=ex1+ex+e2x3+C1+ex2.

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Find the orthogonal trajectories of each of the following families of curves. In each case, sketch or computer plot several of the given curves and several of their orthogonal trajectories. Be careful to eliminate the constant from y'for the original curves; this constant takes different values for different curves of the original family, and you want an expression for y'which is valid for all curves of the family crossed by the orthogonal trajectory you are trying to find. See equations (2.10)to (2.10)

y=kxn. (Assume that n is a given number; the different curves of the family have different values of k.)

Find the orthogonal trajectories of each of the following families of curves. In each case, sketch or computer plot several of the given curves and several of their orthogonal trajectories. Be careful to eliminate the constant from y'for the original curves; this constant takes different values for different curves of the original family, and you want an expression for y'which is valid for all curves of the family crossed by the orthogonal trajectory you are trying to find. See equations (2.10)to (2.12)

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Find the orthogonal trajectories of each of the following families of curves. In each case, sketch or computer plot several of the given curves and several of their orthogonal trajectories. Be careful to eliminate the constant from y'for the original curves; this constant takes different values for different curves of the original family, and you want an expression for y'which is valid for all curves of the family crossed by the orthogonal trajectory you are trying to find. See equations 2.10to 2.12.

(y-1)2=x2+k

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