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Find the general solutions of the following equations and compare computer solutions.

D2(D1)2(D+2)3y=0

Short Answer

Expert verified

The general solution isy=(c1x+c2)+(c3x+c4)ex+(c5x2+c6x+c7)e2x.

Step by step solution

01

 Step 1: Given information from question

Given equation isD2(D1)2(D+2)3y=0

02

Differential equation

Differential equation:

A differential equation is a formula that connects the derivatives of one or more unknown functions. Functions are used to represent physical quantities, derivatives are used to characterise their rates of change, and differential equations are used to define a relationship between them in applications.

03

Calculate the general solution

Rewriting the auxiliary equation

DD(D1)(D1)(D+2)(D+2)(D+2)y=0

Which is mean that this is seventh order differential equation. It is found that the general solution for any differential that has auxiliary equation with unequal real roots which is,

y=c1ea1x+c1ea2x+..+cneanx

04

Calculate the second solution of differential equation 

Usethe second root, which is D=1, then find the second solution of this differential equation

(Da1)(Da2)..(Dan)y=0y=c2ex

Here. a1=a2=anthe solution for such equation is

y=(c1xn1+c2xn2+..+cnxnn)e(n1)x

Therefore, the solution of D2y=0is

y=c1x+c2

The solution of(D1)2y=0is

y=(c3x+c4)ex

The solution of (D+2)2y=0is

y=(c5x2+c6+c7)e2x

And the general solution for our auxiliary equation is a linear combination of the solutions of the simpler equation which is

y=(c1x+c2)+(c3x+c4)ex+(c5x2+c6x+c7)e2x.

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Most popular questions from this chapter

Find the orthogonal trajectories of each of the following families of curves. In each case, sketch or computer plot several of the given curves and several of their orthogonal trajectories. Be careful to eliminate the constant from y'for the original curves; this constant takes different values for different curves of the original family, and you want an expression for y'which is valid for all curves of the family crossed by the orthogonal trajectory you are trying to find. See equations (2.10)to (2.12)

y=kx2

Find the orthogonal trajectories of each of the following families of curves. In each case, sketch or computer plot several of the given curves and several of their orthogonal trajectories. Be careful to eliminate the constant from y'for the original curves; this constant takes different values for different curves of the original family, and you want an expression for y'which is valid for all curves of the family crossed by the orthogonal trajectory you are trying to find. See equations (2.10)to (2.12)

x2+y2=cost.

Solve the equation for the rate of growth of bacteria if the rate of increase is proportional to the number present but the population is being reduced at a constant rate by the removal of bacteria for experimental purposes

A solution containing 90% by volume of alcohol (in water) runs at 1 gal/min into a 100-gal tank of pure water where it is continually mixed. The mixture is withdrawn at the rate of 1 gal/min. When will it start coming out 50% alcohol?

(a) Show that D(eaxy)=eax(D+a)y,D2(eaxy)=eax(D+a)2y, and so on; that is, for any positive integral n, Dn(eaxy)=eax(D+a)ny.

Thus, show that ifis any polynomial in the operator D, then L(D)(eaxy)=eaxL(D+a)y.

This is called the exponential shift.

(b) Use to show that (D-1)3(exy)=exD3y,(D2+D-6)(e-3xy)=e-3x(D2-5D)y..

(c) Replace Dby D-a, to obtain eaxP(D)y=P(D-a)eaxy

This is called the inverse exponential shift.

(d) Using (c), we can change a differential equation whose right-hand side is an exponential times a

polynomial, to one whose right-hand side is just a polynomial. For example, consider

(D2-D-6)y=10×e2x; multiplying both sides by e-3xand using (c), we get

e-3x(D2-D-6)y=[D+32-D+3-6"]"ye-3x=(D2+5D)ye-3x=10x

Show that a solution of (D2+5D)u=10xis u=x2-25x; then or use this method to solve Problems 23 to 26.

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