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Find the general solution of the following differential equations (complementary function + particular solution). Find the particular solution by inspection or by(6.18),(6.23), or(6.24), .Also find a computer solution and reconcile differences if necessary, noticing especially whether the particular solution is in simplest form [see(6.26) andthe discussion after].

2y''+y'=2x

Short Answer

Expert verified

The general solution given by differential equation isy(x)=C1+C2ex2+x24x

Step by step solution

01

Given data. 

Given equation is2y''+y'=2x

02

General solution of differential equation. 

A general solution to the nth order differential equation is one that incorporates a significant number of arbitrary constants. If one uses the variable approach to solve a first-order differential equation, one must insert an arbitrary constant as soon as integration is completed.

03

Find the general solution of given differential equation.2y''+y'=2x

The given differential equation is

2y''+y'=2x2D2+D=2x

The auxiliary equation can be written as

2m2+m=0m(2m+1)=0m=0,12

Solve complementary function and particular integral.

C.F=C1+C2ex2

P.I=12D2+D2x1D(2D+1)2x1D1+2D-12x1D(12D)2x

Solve the equation further

1D(2x4)x24xP.I=x24x

Solution of the differential equation can be written as,

y(x)=C1+C2ex2+x24x

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Most popular questions from this chapter

Using (3.9), find the general solution of each of the following differential equations. Compare a computer solution and, if necessary, reconcile it with yours. Hint: See comments just after (3.9), and Example .

(1+ex)y+2exy=(1+ex)

Find the orthogonal trajectories of each of the following families of curves. In each case, sketch or computer plot several of the given curves and several of their orthogonal trajectories. Be careful to eliminate the constant from y'for the original curves; this constant takes different values for different curves of the original family, and you want an expression for y'which is valid for all curves of the family crossed by the orthogonal trajectory you are trying to find. See equations 2.10to 2.12.

(y-1)2=x2+k

Using Problems 29 and 31b, show that equation (6.24) is correct.

Several Terms on the Right-Hand Side: Principle of Superposition So far we have brushed over a question which may have occurred to you: What do we do if there are several terms on the right-hand side of the equation involving different exponentials?

In Problem 33 to 38 , solve the given differential equations by using the principle of superposition [see the solution of equation (6.29) . For example, in Problem 33 , solve three differential equations with right-hand sides equal to the three different brackets. Note that terms with the same exponential factor are kept together; thus a polynomial of any degree is kept together in one bracket.

y"-5y'+6y=2ex+6x-5

Problems 2 and 3, use (12.6) to solve (12.1) when f(t)is as given.f(t)=sinωt

Using Problems 29 and 31b show that equation (6.24) is correct.

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