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Prove that an absolutely convergent series m=1anis convergent. Hint: Putbn=an+|an|. Then theare nonnegative; we have|bn|2|an|andan=bn-|an|

Short Answer

Expert verified

Define a sequencebn=an+|an| so that for every. Now use |bn|2|an|to get a condition form=1bn and then make use of the first equation again to finish the proof.

Step by step solution

01

Significance of alternating series

If the terms' absolute values gradually decline to zero, or if|an+1||an|andlimnan=0, then an alternating series converges.

02

Finding convergence

Let us consider the hint, the sequence can be defined now:

bn=an+|an|

so that. Also see that the following stands:

|bn|2|an|

Now if we sum both sides and take into account thatlocalid="1658730771138" n=0anseries is absolutely convergent, we get:

localid="1658730630238" n=0bn=n=0bn<2ρ

Where ρis defined as n=0an=ρ. The first equality in the previous equation stands because bn>0.

03

Applying convergence

The series n=0bnis convergent. Now using the equation 1 can write:

localid="1658730886396" n=0an=n=0bn=n=0an

Proved that n=0bnis convergent and n=0anis convergent by assumption so the n=0anseries must also converge.

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